Answer:
-5/3
Step-by-step explanation:
Do PEMDAS
8 - 11 = -3
-3 ^ 3 = -27
-(-27) = 27
I-14I = 14
3 x 14 = 42
27 - 42 = -15
2^4 = 16
16 - 7 = 9
-15/9 = -5/3
V = 4/3πr³
V= 4/3π(4.8)³
V= 4/3π(110.592)
V=147.456π
Answer:
![f(x)=4\sqrt[3]{16}^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D)
Step-by-step explanation:
We believe you're wanting to find a function with an equivalent base of ...
![4\sqrt[3]{4}\approx 6.3496](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B4%7D%5Capprox%206.3496)
The functions you're looking at seem to be ...
![f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x](https://tex.z-dn.net/?f=f%28x%29%3D2%5Csqrt%5B3%5D%7B16%7D%5Ex%5Capprox%202%5Ccdot2.5198%5Ex%5C%5C%5C%5Cf%28x%29%3D2%5Csqrt%5B3%5D%7B64%7D%5Ex%3D2%5Ccdot%204%5Ex%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D%5Capprox%204%5Ccdot%206.3496%5Ex%5C%20%5Cleftarrow%5Ctext%7B%20this%20one%7D%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B64%7D%5E%7B2x%7D%3D4%5Ccdot%2016%5Ex)
The third choice seems to be the one you're looking for.
Answer:
24 times
Step-by-step explanation:
cone is used to fill cylinder
conevolume times x=cylindervolume
so
x=cylinderv/conev
cylinderv=hpir^2
conevolume=1/3hpir^2
cylinder:
v=hpir^2
r=10
h=20
v=20*pi*10^2=2000π
cone=1/3hπr²
r=5
h=10
v=1/3(10)π5²=250π/3
volume of cylinder ÷ volume of cone
= 2000π ÷ (250π÷3)
= 6000π ÷ 250π
= 600÷25
= 24
please mark me brainliest
Linear equations can be written different ways such the form y=mx+b, where m is the slope of the line and b is the y intercept.
We can substitute our given coordinates into the equations to find out which one is correct.
A:


For this equation, when the value of x is - 3, y is 2. This means that A is the correct equation as it passes through the given coordinate (-3,2), and has a slope (m) of 2/3.