1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katyanochek1 [597]
4 years ago
12

Be sure to answer all parts. Pure HN3 (atom sequence HNNN) is explosive. In aqueous solution, it is a weak acid that yields the

azide ion, N3−. Draw one resonance structure for N3− and one resonance structure for HN3. Include all lone pair electrons and nonzero formal charges in your structures.

Chemistry
1 answer:
Arte-miy333 [17]4 years ago
4 0

Answer:HN3 is a weak acid as its conjugate base anion formed after deprotonation is very unstable.

Kindly refer the attachments for the resonating structures of HN3 and N3- anion.

Explanation:

Kindly refer the attachment for structure of azide ion.

The azide ion is a explosive due to the highly unstable structure of azide ion and a strong tendency for the formation of nitrogen  molecule which is stable.

So azides decompose very quickly to give nitrogen molecule which is very stable on account of triple bond.

The azide ion basically has 3 resonating forms .There are 3 Nitrogen atoms and the central nitrogen atom is positively  charged as it forms double bonds with each of the two nitogens.

Although there is some delocalization of charges  present on the three nitrogen atoms but the fact is that in the structure there are  charges present of different polarity  .So one of the nitrogen is positively charged and other two nitrogens are negatively charged. Due to this separation of charges of different polarity this unstability arises. It is nitrogen only which has to carry the postive as well as negative charge.

The resonance structure of HN₃ is also similar as in this structure also there is charge separation between positive and negative charges but here due to the presence of hydrogen one of the negative charge is neutralised and molecule is sightly neutralized as no nitrogen atom has to bear 2 negative charge as in the case of azide ion.

Kindly refer the attachments:  

You might be interested in
Reasoning you used to decide if something was made of molecules.​
sasho [114]

Answer:

Whether something is a molecule or not depends on the type of bond that is formed when its atoms join together. In general, electrons can be shared between atoms (a molecular bond) or electrons can be completely removed from one atom and given to another (an ionic bond). Molecules have molecular bonds.

6 0
4 years ago
What two parts of an amino acid are involved in a peptide bond?
Lemur [1.5K]

Answer:

The answer to your question is below.

Explanation:

Amino acids are composed by one amino group, one carboxyl group and one  chain.

The parts of the amino acid that are involved in a peptide group are the amino group (- NH₂) and the carboxyl group (-COOH).

6 0
3 years ago
At equilibrium, the concentrations of the products and reactants for the reaction, H2 (g) + I2 (g)  2 HI (g), are [H2] = 0.106
lana [24]

Answer:

The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>          

Explanation:

Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M        

Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M

<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)

The equilibrium constant (K_{c}) for the given chemical reaction, is given by the equation:

K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}

<u><em>At the original equilibrium state:</em></u>

K_{c} = \frac {(1.29\: M)^{2}}{(0.106\: M) \times (0.022\: M)}

K_{c} = \frac {1.6641}{0.002332} = 713.59

<u><em>Therefore, at the new equilibrium state:</em></u>

K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}

\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}

\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88

\Rightarrow [HI] = \sqrt {12.88} = 3.589 M

<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>

6 0
3 years ago
How can a magnetic field be used to create an electric current
nadezda [96]

Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. One way to explore the direction of a magnetic field is with a compass, as shown by a long straight current-carrying wire in.

3 0
3 years ago
Read 2 more answers
Which of these is an example of a chemical change?
Lady_Fox [76]
The only one example of a chemical change would be:

B. Leaving cheese out to get moldy.

Because there is a chemical reaction.
6 0
3 years ago
Read 2 more answers
Other questions:
  • 5 Points
    6·2 answers
  • Please Help I will reward brainliest
    6·2 answers
  • In a longitudinal wave moving along a spring, what are areas where the coils are farthest apart called?
    5·2 answers
  • A sample of iron with a mass of 50.0 grams absorbs 2500 J of thermal energy. How much would the temperature of this sample chang
    8·1 answer
  • What unit is mass generally measured in
    14·2 answers
  • calculate pressure exerted by 1.255 mol of CI2 in a volume of 5.005 L at a temperature 273.5 k using ideal gas equation
    8·1 answer
  • Please hurry!!! And help!!
    6·2 answers
  • Describe the energy transferred in the endothermic reactions
    11·1 answer
  • What flows directly into the ocean? *
    14·2 answers
  • HELPPPP ASAPP 10 POINTS
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!