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Katyanochek1 [597]
4 years ago
12

Be sure to answer all parts. Pure HN3 (atom sequence HNNN) is explosive. In aqueous solution, it is a weak acid that yields the

azide ion, N3−. Draw one resonance structure for N3− and one resonance structure for HN3. Include all lone pair electrons and nonzero formal charges in your structures.

Chemistry
1 answer:
Arte-miy333 [17]4 years ago
4 0

Answer:HN3 is a weak acid as its conjugate base anion formed after deprotonation is very unstable.

Kindly refer the attachments for the resonating structures of HN3 and N3- anion.

Explanation:

Kindly refer the attachment for structure of azide ion.

The azide ion is a explosive due to the highly unstable structure of azide ion and a strong tendency for the formation of nitrogen  molecule which is stable.

So azides decompose very quickly to give nitrogen molecule which is very stable on account of triple bond.

The azide ion basically has 3 resonating forms .There are 3 Nitrogen atoms and the central nitrogen atom is positively  charged as it forms double bonds with each of the two nitogens.

Although there is some delocalization of charges  present on the three nitrogen atoms but the fact is that in the structure there are  charges present of different polarity  .So one of the nitrogen is positively charged and other two nitrogens are negatively charged. Due to this separation of charges of different polarity this unstability arises. It is nitrogen only which has to carry the postive as well as negative charge.

The resonance structure of HN₃ is also similar as in this structure also there is charge separation between positive and negative charges but here due to the presence of hydrogen one of the negative charge is neutralised and molecule is sightly neutralized as no nitrogen atom has to bear 2 negative charge as in the case of azide ion.

Kindly refer the attachments:  

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3 years ago
A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
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Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

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Which law relates to the ideal gas law?
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<u>Answer:</u> The law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

<u>Explanation:</u>

There are 4 laws of gases:

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Mathematically,

P_1V_1=P_2V_2

  • <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

  • <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

  • <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Hence, the law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

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