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3 years ago

Plz help me 50 points and plz no crazys things

Chemistry

2 answers:

alexandr1967 [171]3 years ago

7 0

V i n e g a r ٩(๑❛ᴗ❛๑)۶

jonny [76]3 years ago

7 0

Vinegar - <em>litmus paper shows for the presence of acidity and vinegar is the only acidic substance in the options</em><em>.</em>

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A cylinder with a radius of 5.6 cm and a height of 10.7 cm has what volume? (You can look up the formula for the volume of a cyl

Keith_Richards [23]

Answer:

$V=1054.2cm^{3}$

Explanation:

1. First take the cylinder volume formula:

$V=\pi.r^{2}.h$

2. Then take the values for the radius and the height of the cylinder and replace them into the formula:

$V=\pi*(5.6cm)^{2}*(10.7cm)$

3. Solve the equation:

$V=\pi*(31.36cm^{2})*(10.7cm)$

$V=\pi*335.5cm^{3}$

$V=1054.2cm^{3}$

6 0

3 years ago

Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).A

Bond [772]

Answer:

The molar solubility of carbon dioxide gas is $4.662\times 10^{-6} M$ .

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{CO_2}=K_H\times p_{liquid}$

where,

$K_H$ = Henry's constant = $3.50\times 10^{-2}mol/L.atm$

$p_{CO_2}$ = partial pressure of carbonated drink

$p_{CO_2}=p\times \chi_{CO_2}$

where = p = Total pressure = 0.400 atm

$\chi_{CO_2}$ = mole fraction of $CO_2=3.33\times 10^{-4}$

$p_{CO_2}=0.400 atm\times 3.33\times 10^{-4} =0.0001332 atm$

Putting values in above equation, we get:

$C_{CO_2}=3.5\times 10^{-2}mol/L.atm\times 0.0001332 atm\\\\C_{CO_2}=4.662\times 10^{-6} M$

Hence, the molar solubility of carbon dioxide gas is $4.662\times 10^{-6} M$ .

8 0

2 years ago

The volume of a sample of gas is 0.5 L and the pressure is 0.98 atm. The volume is increased to 1.0 L. Show the set

meriva

Given,

P1 = 0.98 atm

V1 = 0.5 L

V2 = 1.0 L

P2 = ?

Solution,

According to Boyle's Law,

P1V1 = P2V2

0.98 × 0.5 = 1.0 × P2

P2 = 0.98 × 0.5 × 1.0

P2 = 0.49 atm

Answer - The new pressure is 0.49 atm.

5 0

3 years ago

How many moles of oxygen would be required to produce 5 mol of water? (Remember sig figs)

Vikki [24]

Answer:

Since moles are just "some number of particles", and since one O2 molecule contains enough oxygen for two H2O molecules, you need 2.5 moles of O2 for 5 moles of H2O.

7 0

2 years ago

Think about a hot summer afternoon at the beach

NeTakaya

A. Would be the correct answer :-)

3 0

2 years ago

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