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lbvjy [14]
3 years ago
14

Plz help me 50 points and plz no crazys things

Chemistry
2 answers:
alexandr1967 [171]3 years ago
7 0
V i n e g a r ٩(๑❛ᴗ❛๑)۶
jonny [76]3 years ago
7 0

Vinegar - <em>litmus paper shows for the presence of acidity and vinegar is the only acidic substance in the options</em><em>.</em>

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HELP ME ASAP WITH MY SCIENCE HW! I’m currently failing this class
lakkis [162]

Explanation:

for claim: you would put something like plant c will grow the tallest.

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reasoning they all had the same care just put in different places and on the window seal is the best place to grow plants since it grew the tallest.

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3 years ago
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The electron cloud model describes the __of electrons in an atom.
Alex Ar [27]

Answer:

it's location

Explanation:

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3 years ago
4.2 grams of magnesium metal reacts with excess gold III chloride to form 5.9 grams of gold and also magnesium chloride. What is
Margaret [11]

Answer:

???

Explanation:

3 0
3 years ago
The molar mass of a certain gas is 49 g. What is the density of the gas in g/L at STP?
snow_tiger [21]

Answer:

\boxed{\text{2.2 g/L}}

Explanation:

We can use the Ideal Gas Law to calculate the density of the gas.

   pV = nRT

      n = m/M           Substitute for n

   pV = (m/M)RT     Multiply both sides by M

pVM = mRT            Divide both sides by V

  pM = (m/V) RT

     ρ = m/V             Substitute for m/V

 pM = ρRT              Divide each side by RT

\rho = \frac{pM }{RT}

Data:

p = 1.00 bar

M = 49 g/mol

R = 0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

Calculation:

ρ = (1.00 × 49)/(0.083 14 × 273.15) = 2.2 g/L

The density of the gas is \boxed{\text{2.2 g/L}}.

8 0
4 years ago
Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that
Alchen [17]

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>C_4_H8 in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

<u />

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

<u />

See figure 1 to further explanations.

I hope it helps!

<u />

<u />

8 0
3 years ago
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