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klio [65]
4 years ago
14

A 20.0 F capacitor initially charged to 30.0 uC is discharged through a 3.00 k resistor. How long does it take to reduce the cap

acitor's charge to 15.0 C? Express your answer with the appropriate units. ?
Physics
1 answer:
Maslowich4 years ago
3 0

Answer:

t = 0.04159 s

Explanation:

when a capacitor and resister are connected in series. charge on its plates decreases exponentially

q = qo * e^{\frac{-t}{RC}}

where,

CHARGE q  =15.0 C

INITIAL CHARGE q_0 = 30.0 uc

Resistor R = 20.0 F

capacitor C  = 3.00

15 = 30* e^{\frac{- t}{(20* 10^{-6} * 3* 1000)}

t = 0.04159 s

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