When the spring is stretched by 15.2 cm = 0.152 m, the spring exerts a restorative force with magnitude (due to Hooke's law)
where 
is the spring constant. Solve for .
The amount of work required to stretch or compress a spring by 
from equilibrium length is
Then the work needed to stretch the spring by 15.2 cm is
and by 15.2 + 13.7 = 28.9 cm is
so the work needed to stretch from 15.2 cm to 28.9 cm from equilibrium is
Answer: Multicellular organism
Explanation:
Multicellular organisms refer to living things that have more than a single cell as opposed to unicellular organisms such as bacteria. Humans as well as all animals and land plants fall under this classification.
Multicellular organisms can live longer because new cells can be produced when others die. They are also larger due to the presence of many different cells which then specialize in different roles to ensure the survival of the organism.
Answer:
a) 17.086m
b) 0.1671 m
Explanation:
Given data: speed of water through the hose = 1.81 m/s
through the nozzle = 18.3 m/s
We know that maximum height of an object with upward velocity v is given by,
a) H = v^2/2g
where H is the maximum height water emerges
= 18.3^2/(2×9.8) = 17.086 m answer
b) Again,
H = v^2/2g
= 1.81^2/(2×9.8) = 0.1671 m
Answer:
Explanation:
From the question we are told that
Voltage 
Generally in a case of Y_connection 
is mathematical represented as
Generally voltage drop across phase A
Generally voltage drop across phase B
Generally voltage drop across phase C
Answer:
Explanation:
In the whole process , potential energy of the cart is converted into kinetic energy . At the top of the vertical loop , the whole of potential energy is regained and kinetic energy becomes zero if we release the cart from a height of 2R because difference of height between lowest and highest point of motion is 2R . In that case kinetic energy at top = 0 , velocity v = 0
At the top , weight mg is acting which is providing centripetal force . So cart must have some velocity at the top . If it be v
mv²/R = mg
v = √ gR .
For that purpose , the cart must be released from a height greater than 2R .
The extra height beyond 2R will make the velocity at the top non-zero.
