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Stels [109]
4 years ago
12

A force of 6.0 Newton’s gives a 2.0kg block an acceleration of 3.0m/s to the right. The force of friction acting on the block is

?
Physics
1 answer:
DochEvi [55]4 years ago
3 0
The force of friction is zero.
Using F = m a = the force needed is 6 N which means no friction can be acting.
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Which of the following is a graph of the velocity of an object as it falls fromrest if drag is not ignored? Explain your choice
MariettaO [177]

The air drag is a force that depends on the speed of an object relative to the wind. Under certain conditions, it can be modeled as:

F=-bv

Where b is a constant.

As a falling object reaches a speed so that its weight is cancelled out by the air drag, the object will reach a maximum velocity.

In a speed vs time gaph, the speed would approach the maximum speed like an asymptote.

On the other hand, since the object falls from rest, the initial speed on the graph must be zero.

Taking these considerations into account, the correct graph for the movement of an object that falls from rest if air drag is not ignored, is option B.

7 0
1 year ago
The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 {\rm rpm} .
damaskus [11]

Answer:

5833.33

Explanation:

\alpha = Angular acceleration

\theta = Number of revolutions

\omega_i = Initial angular speed = 0

t = Time taken = 2 s

Final angular speed

\omega_f=\dfrac{350000}{60}=5833.33\ rps

From the equation of rotational motion we have

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{5833.33-0}{2}\\\Rightarrow \alpha=2916.665\ rev/s^2

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2916.665\times 2^2\\\Rightarrow \theta=5833.33\ rev

The number of revolutions is 5833.33

6 0
3 years ago
Yosemite falls, in california, has a total height of 73,900 cm. what is this height in meters?
Hunter-Best [27]
Yosemite falls has a total height of 73,900 cm it means it heights 739 meters
6 0
3 years ago
A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail
grandymaker [24]
The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

                                 (2 m/s  +  49 m/s)  =  51 m/s .
7 0
3 years ago
ppose that you hold a vibrating 340 Hz tuning fork near a guitar string that is vibrating at 350 Hz. What you hear is?
galben [10]

Answer:

A beat with the frequency of 10Hz.

Explanation:

The frequencies from the tuning fork and guitar will cancel each other.

The frequency of tuning fork = 340Hz

The frequency of guitar string= 350Hz

The offset = 350Hz - 340Hz = 10Hz

A 10Hz frequency sound is still heard.

3 0
3 years ago
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