Answer:
1. From sin²θ +cos²θ =1 and sinθ=-2/3, we see that cosθ=√(1-sin²θ) or cosθ=√5/3, where the sign of cosine is positive as it is in Quadrant IV. x lies in 4th quadrant , cos x is +ve. , cos x = √5/3. Answer.
answer : cos x = √5/3
2. 4/3
3. sin (- theta) = - sin (x) so sin x = 1/6
tan = sin / cos = 1/6 / cos = - sqrt35/35 solve for cos
cos = 1/6 * (-35/sqrt35)
= -35 sqrt35 /210
answer : −35/√210
4. The cosine function is an even function, so cos(θ) = cos(-θ).
The relationship between sin(θ) and cos(θ) is sin(θ) = ±√(1 -cos(θ)^2)
For sin(θ) < 0 and cos(θ) = (√3)/4, sin(θ) = -√(1 -3/16) = -√(13/16)
sin(θ) = -(√13)/4 For sin(θ) < 0 and cos(0) = √(3/4), ...
sin(θ) = -√(1 -3/4) = -√(1/4) sin(θ) = -1/2
answer : -13/√4
5. answer : tan^2 θ ⋅ cos^2 θ = 1 − cos^2 θ would be the first step
Answer:
C
Step-by-step explanation:
x - 3 < -9
simplifies to x < -6, which is to the left with an open circle
x + 5<u>></u> 12
simplifies to x <u>></u> 7, which is to the right a closed circle
B * 3 < 140
B being the number of books Frank owns. Because tripling the amount of books he owns is still less than the amount of book Emily owns, b*3 has to be less than 140
Why did you delete my answer
Answer:
512 ft.
Step-by-step explanation:
From the parking lot at the Red Hill Shopping Center, the angle of sight (elevation) to the top of the hill is about 25. From the base of the hill you can also sight the top but at an angle of 55. The horizontal distance between sightings is 740 feet. How high is Red Hill? Show your subproblems.
Solution:
Let x be the distance from the base of the hill to the middle of the hill perpendicular to the height, let h be the height of the hill. Therefore:
tan 25 = h/(x + 740)
h = (x + 740)tan 25 (1)
tan 55 = h / x
h = x tan 55 (2)
Hence:
(x + 740)tan 25 = xtan 55
0.4663(x + 740) = 1.428x
0.4663x + 345.07 = 1.428x
0.9617x = 345.07
x = 359 ft.
h = xtan55 = 359 tan(55) = 512 ft.
