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vaieri [72.5K]
2 years ago
7

Hey guys, I need a proof on whether water is wet or not. I need a detailed scientific proof. THIS IS NOT A JOKE!

Chemistry
2 answers:
jarptica [38.1K]2 years ago
4 0

Answer:

Water isn't wet by itself, but it makes other materials wet when it sticks to the surface of them.

Explanation:

EastWind [94]2 years ago
3 0
Water isn’t wet, Wetness is a description of our experience with water. What happens to us when we come in contact with water is called being wet
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A compounds empirical formula is H.O. If the formula mass is 34 amu what is the molecular formula?
BigorU [14]

Answer:

C

Explanation:

1. The molecule has to have a ratio of 1 hydrogen to 1 oxygen.

2. Hydrogen = 1amu, Oxygen = 16amu. (2*2)+(16*2) = 34amu

7 0
2 years ago
Which scenario best exemplifies the way a signal is passed down an axon coated with myelin sheath?
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Runners sprinting short distances in a relay race and handing off a baton scenario best exemplify the way a signal is passed down an axon coated with a myelin sheath.

Axons are long extensions of neurons (or nerve cells) involved in the transmission of nerve impulses away from the cell body. Each nerve cell has an axon that is over a foot long. A nerve cell communicates with another nerve cell by transmitting signals from the branches at the ends of the axon.

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Global warming facts
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Cattle contribute to more carbon emissions than all of the worlds transport.
5 0
2 years ago
If an atom has 5 protons, how many electrons does it have?
IRISSAK [1]

Answer:

5

Explanation:

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8 0
3 years ago
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The smell of fresh cut pine is due in part to the cyclic alkene called pinene. Given the following data of pinene: Vapor pressur
Sveta_85 [38]

Answer: Heat of vaporization is 41094 Joules

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at  429 K = 760 torr

P_2 = final pressure at 415 K  = 515 torr

= enthalpy of vaporisation = ?

R = gas constant = 8.314 J/mole.K

T_1= initial temperature =  429 K

T_2 = final temperature = 515 K

Now put all the given values in this formula, we get

\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]

\Delta H=41094J

Thus the heat of vaporization is 41094 Joules

4 0
3 years ago
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