117 mL of 0.210 M K₂S solution
Explanation:
The question asks about the volume of 0.210 M K₂S (potassium sulfide) solution required to completely react with 175 mL of 0.140 M Co(NO₃)₂ (cobalt(II) nitrate).
We have the chemical reaction:
K₂S + Co(NO₃)₂ → CoS + 2 KNO₃
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume
number of moles of Co(NO₃)₂ = 0.140 × 175 = 24.5 mmoles
We see from the chemical reaction that 1 mmole of Co(NO₃)₂ is reacting with 1 mmole of K₂S, so 24.5 mmoles of Co(NO₃)₂ are reacting with 24.5 mmoles of K₂S.
volume = number of moles / molar concentration
volume of K₂S solution = 24.5 / 0.210 = 117 mL
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molar concentration
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According to the second law of thermodynamics, heat energy released by an organism is released into the <span>environment and unusable. This energy is also known as entropy which is defined as the tendency of things to be dispersed and spontaneous. This means that entropy is always random and becomes unavailable energy.</span>
<span>steam at 200°C. particles experience a lot of energy as you increase the temperature.</span>
Answer: The structure for the boron nitride molecule will be linear.
Explanation: When boron and nitrogen combine together to form a compound, the boron element will loose 3 electrons which will be easily accepted by the nitrogen element.
Boron : Atomic number is 5
Electronic configuration: 
To attain stable configuration, boron will loose 3 electrons easily.
Nitrogen : Atomic number is 7
Electronic configuration: 
To attain stable configuration. nitrogen will gain 3 electrons easily.
Hence, to form a molecule with these two elements, there will be 3 bonds present in between them and 1 pair of lone pair will be left on the nitrogen atom.
Structure of boron nitride ( which is linear) is attached in the image below.
The consentration of the soliton is at max,if you are heating up the solution to evaporate then increase in temprature might mean your solute solubility increases
