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bonufazy [111]
2 years ago
6

Daniel is having a BBQ and he's making cheeseburgers. He has two packs of hamburger patties (each

Chemistry
1 answer:
Deffense [45]2 years ago
7 0

Answer: I’d say 16

Explanation:

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When a highly reactive metal, such as lithium (Li), is mixed with a highly reactive nonmetal, such as chlorine (Cl), they will m
Usimov [2.4K]

Answer:

True

Explanation:

lithium atoms lose one electron each while chlorine atoms gain one electron each

8 0
3 years ago
the triple point of co2 occurs at nearly 1000 times greater pressure and at a lower temperature than the triple point of h2o. ba
IceJOKER [234]

Since liquid CO2 cannot exist at pressures lower than 5.11 atm, the triple point is defined as 56.6 °C and 5.11 atm.

Are CO2 liquids explosive?

Although it can impair judgement at high doses, carbon dioxide is neither poisonous nor combustible. Asphyxiation is typically seen as the primary risk associated with CO2. The Boiling Liquid Expanding Vapour Explosion, however, is a serious risk connected to compressed CO2 (BLEVE)

What PSI does CO2 turn into liquid at?

Only at pressures more than 5.1 atm does liquid carbon dioxide form; the triple point of carbon dioxide is approximately 518 kPa at 56.6 °C. Depending on the pressure, the liquid's boiling point ranges from -70°F to +88°F. The expansion ratio when vaporised at 60°F is 535:1. CO2 is a gas or liquid.

Toknw more about Liquid CO2 visit:

https://brainly.in/question/16890479

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5 0
1 year ago
Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g<img src="https:/
Ivenika [448]

Answer:

The answer to your question is:   C₃H₃O  This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

CO₂ = 3.2007 g

H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

MW H2O = 18 g

For Carbon

                                     44 g -------------------- 12 g

                                     3.2007 g ------------    x

                                      x = (3.2007 x 12) / 44

                                      x = 0.8729 g of Carbon

                                     12 g of C --------------  1 mol

                                     0.8729 g --------------  x

                                     x = (0.8729 x 1) / 12

                                     x = 0.0727 mol of Carbon

For Hydrogen

                                 18 g ---------------------- 1 g

                              1.3102 g -------------------  x

                                   x = (1.3102 x 1) / 18

                                  x = 0.0727 g of Hydrogen                                      

                                  1 g ------------------------ 1 mol

                                  0.0727g ----------------  x

                                  x = (0.0727 x 1)/1

                                  x = 0.0727 mol of Hydrogen

For oxygen

                    g of Oxygen = g of sample - g of Carbon - g of hydrogen

                    g of Oxygen = 1.3109 - 0.8709 - 0.0727

                    g of Oxygen = 0.3673

                                  16 g of Oxygen ------------- 1 mol of O

                                  0.3673 g ---------------------   x

                                   x = (0.3673 x 1)/ 16

                                   x = 0.0230 mol of Oxygen

Divide by the lowest number of moles

Carbon              0.0727 / 0.023  = 3.1  ≈ 3

Hydrogen         0.0727 / 0.023 = 3.1  ≈ 3

Oxygen             0.0230 / 0.023 = 1

                                        C₃H₃O

8 0
3 years ago
Read 2 more answers
What is the charge associated with each side of the HCl molecule?
Alexandra [31]

HCl is a polar molecule with the hydrogen part being partial positive while the chlorine end being partial negative. This is because hydrogen has an electronegativity of 2.1, and chlorine has an electronegativity of 3.0. This means that chlorine attracted most of the electron cloud of molecule hence is the negative dipole, The dipole moment of HCl is 1.08 D (debyes). A Debye is equal to 3.34 x 10-30 coulomb-meters (C-m). The charge of each molecule is o.176+ for H and 0.176- for the Cl

3 0
3 years ago
Read 2 more answers
How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?
nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 2 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the diluted solution (C₂): 0.1 M
  • Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

4 0
3 years ago
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