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uranmaximum [27]
3 years ago
13

rutherford's experiment with gold estimate the radius of a gold atom to be approximately 1x10^-9 cm. Suppose the radius of the n

ucleus is the same as a basketball. Would the volume of the atom be bigger or smaller than that of a typical domed athletic stadium? Show a little math to support your answer.
Chemistry
1 answer:
Lemur [1.5K]3 years ago
3 0
I'm am pretty sure that the answer is -2
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A student is given a 2.002 g sample of unknown acid and is told that it might be butanoic acid, a monoprotic acid (HC4H7O2, equa
Elina [12.6K]

<u>Answer:</u> The identity of the unknown acid is butanoic acid or ascorbic acid.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of NaOH solution = 0.570 M

Volume of solution = 39.55 mL

Putting values in above equation, we get:

0.570M=\frac{\text{Moles of NaOH}\times 1000}{39.55}\\\\\text{Moles of NaOH}=\frac{0.570\times 39.55}{1000}=0.0225mol

The chemical equation for the reaction of NaOH and monoprotic acid follows:

NaOH+HX\rightarrow NaX+H_2O

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HX

So, moles of monoprotic acid = 0.0225 moles

The chemical equation for the reaction of NaOH and diprotic acid follows:

2NaOH+H_2X\rightarrow 2NaX+2H_2O

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of diprotic acid

So, moles of diprotic acid = \frac{0.0225}{2}=0.01125moles

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

  • <u>For butanoic acid:</u>

Mass of butanoic acid = 2.002 g

Molar mass of butanoic acid = 88 g/mol

Putting values in above equation, we get:

\text{Moles of butanoic acid}=\frac{2.002g}{88g/mol}=0.02275mol

  • <u>For L-tartaric acid:</u>

Mass of L-tartaric acid = 2.002 g

Molar mass of L-tartaric acid = 150 g/mol

Putting values in above equation, we get:

\text{Moles of L-tartaric acid}=\frac{2.002g}{150g/mol}=0.0133mol

  • <u>For ascorbic acid:</u>

Mass of ascorbic acid = 2.002 g

Molar mass of ascorbic acid = 176 g/mol

Putting values in above equation, we get:

\text{Moles of ascorbic acid}=\frac{2.002g}{176g/mol}=0.01137mol

As, the number of moles of butanoic acid and ascorbic acid is equal to the number of moles of acid getting neutralized.

Hence, the identity of the unknown acid is butanoic acid or ascorbic acid.

5 0
3 years ago
Sulfuric acid dissolves aluminum metal according to the following reaction:
Fiesta28 [93]

Answer:

m_{H_2SO_4}=81.7gH_2SO_4

m_{H_2}=1.67gH_2

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

2Al (s) + 3H_2SO_4 (aq)\rightarrow  Al _2(SO4)_3 (aq) + 3H_2 (g)

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2

Best regards.

3 0
3 years ago
The store paid 4.50 for a book and sold it for $7.65.what is the profit as a percent of the cost to the store? A. 3. 15% b. 58.8
xeze [42]

Answer: This would be C.) 70%

Explanation:

4 0
2 years ago
Perform the following conversions:<br> (a) 68°F (a pleasant spring day) to °C and K.
IgorC [24]

Converting  temperature of 68°F to °C gives 20 °C.

Converting  temperature of 68°F to K gives 293 K.

<h3>What is temperature conversion?</h3>

Temperature conversion is the process of converting  the measurement units of the temperature recorded in a particular unit to another unit.

The various units of Temperature include;

  • degree Celsius
  • degree Fahrenheit
  • degree Kelvin

Temperature is measured with thermometer and it records the hotness or coldness of a body.

<h3>Converting  68°F to °C</h3>

F = 1.8C + 32

(F - 32/1.8) = C

(68 - 32) / 1.8 = C

20 ⁰C = 68 ⁰F

<h3>Converting  20°C to K</h3>

0 °C  = 273 K

20 °C  = 273 + 20 = 293 K

Learn more about temperature conversion here: brainly.com/question/23419049

#SPJ1

3 0
1 year ago
NaOH  + H2SO4 =
mariarad [96]
2NaOH+H_2SO_4\Rightarrow\ Na_2SO_4+2H_2O\\&#10;NaOH+HNO_3\Rightarrow\ NaNO_3+H_2O\\&#10;Cu(OH)_2+2HCl\Rightarrow\ CuCl_2+2H_2O\\&#10;Cu(OH)2+H_2SO_4\Rightarrow\ CuSO_4+2H_2O\\&#10;Cu(OH)_2+2HNO_3\Rightarrow\ Cu(NO_3)_2+2H_2O
3 0
2 years ago
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