rutherford's experiment with gold estimate the radius of a gold atom to be approximately 1x10^-9 cm. Suppose the radius of the n
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Answer:
the energy of the third excited rotational state
Explanation:
Given that :
hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm
Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.
Thus; the reduced mass μ =
μ =
μ =
∵ 1 μ = 1.66 × 10⁻²⁷ kg
μ =
μ = 1.6139 × 10⁻²⁷ kg
The rotational level Energy can be expressed by the equation:
where ;
J = 3 ( i.e third excited state) &
We know that :
1 J =