<span>By using the mole ratio, we can determine that 2 moles of NH3 are made when 3 moles of hydrogen gas are present. The numbers in front of the chemicals tell us the relative amounts consumed and produced. Since there is a 3 in front of H2 and a 2 in front of NH3, this tells us that for every 3 moles of H2 gas used, 2 moles of NH3 are made.</span>
Answer:
B. Patterns can help explain observations.
Explanation:
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Answer:
n = 0.0814 mol
Explanation:
Given mass, m = 35.7g
The molar mass of Tin(IV) bromate, M = 438.33 g/mol
We need to find the number of moles of bromine. We know that,
No. of moles = given mass/molar mass
So,

So, there are 0.0814 moles of bromine in 35.7g of Tin(IV) bromate.
The volume occupied by 2.00 moles of nitrogen gas at the same temperature and pressure will be
0.500 moles = 11.2 Liters
what about 2 moles =? liters
by cross multiplication
= 11.2 liters x 2moles/ 0.500 moles = 44.8 liters