1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonbull [250]
3 years ago
9

A 45.9 g sample of a metal is heated to 95.2°c and then placed in a calorimeter containing 120.0 g of water (c = 4.18 j/g°c) at

21.6°c. the final temperature of the water is 24.5°c. which metal was used?
Chemistry
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

Iron

Explanation:

Heat released by the metal sample will be equivalent to the heat absorbed by  water.

But heat = mass × specific heat capacity × temperature change

Thus;

Heat released by the metal;

= 45.9 g × c ×(95.2 -24.5) , where c is the specific heat capacity of the metal

= 3245.13c joules

Heat absorbed by water;

= 120 g × 4.18 J/g°C × (24.5-21.6)

= 1454.64 joules

Therefore;

3245.13c joules = 1454.64 joules

c = 1454.64/3245.13

  = 0.448 J/g°C

The specific heat capacity of the  metal sample is 0.448 J/g°C. The metal use is most likely, Iron.

You might be interested in
Which statement describes a physical property of copper?
Dmitrij [34]

Answer is: It can be reshaped by a force.

Physical property can be observed and measured without any changes in molecular composition. The same substance is present before and after the change, changing the shape is physical change.

Copper reaction with acid, ignition and combination with oxygen are chemical change (chemical reaction), because new substances are formed, the atoms are rearranged and the reaction is followed by an energy change.

7 0
3 years ago
Read 2 more answers
Which observation about methane (ch4) can be explained using the orbital hybridization theory?
MissTica
<span>All 4 C-H bonds are identical.

Hybridisation or hybridization is the idea of blending atomic orbitals into new hybrid orbitals, with various energies, shapes, and so on, than the component atomic orbitals, appropriate for the matching of electrons to make chemical bonds in valence bond theory.
</span>
7 0
3 years ago
Carbon dioxide (CO2) is a common compound made of
marishachu [46]
Answer is D 2 elements and a total of 3 atoms
8 0
3 years ago
What are the products of the combustion of a hydrocarbon?
Oxana [17]

Answer:

I think carbon and hydrogen

7 0
3 years ago
Read 2 more answers
A glass blower can bend and shape a piece of glass that has been heated. Is glass a crystalline or an amorphous solid?
zavuch27 [327]

it would be a crystalline solid, because it could be extended in multiple directions.

5 0
3 years ago
Other questions:
  • A gas has a volume of 6.46L at 1.06 atm and 77.2°C. What is the volume of the gas (in L) at STP​
    11·2 answers
  • Help! I need a little help on faulty parallel structure
    11·1 answer
  • Sodium is a metal, like copper, suggest reasons why sodium cannot be used in electrical wires
    14·1 answer
  • The chemical equation below shows the burning of magnesium with oxygen to form magnesium oxide 2Mg + 02 --&gt; 2MgO the molar ma
    10·2 answers
  • A molecule with the formula ax3 uses __________ to form its bonds. multiple choice sp2 hybrid orbitals sp hybrid orbitals sp3d2
    13·2 answers
  • A _____ fireplace continues to radiate heat even after the fire is extinguished.
    6·2 answers
  • The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO). 2Mg + O2 mc019-1
    6·2 answers
  • Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH4) by the following process: Hydrogen cyanide is used t
    10·1 answer
  • A small hole in the wing of a space shuttle requires a 16.2 cm2 patch. (b) If the patching material costs NASA $3.58/in2, what i
    13·1 answer
  • What is the difference between a substance that low concentration and one high concentration
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!