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3 years ago

A raffle is being held to benefit the local animal shelter. They sell 903 tickets that do

Mathematics

1 answer:

Effectus [21]3 years ago

6 0

Answer: A raffle is being held to benefit the local animal shelter. They sell 903 tickets that do

not win any prize, 18 tickets that win a free adoption (valued at $20), and one ticket

that wins $171 worth of pet supplies and toys. If they are selling the tickets for $5

each, how much should the shelter expect to earn for each ticket sold?

Round to the nearest cent, as needed.

sorry if it appears messy!!!

Step-by-step explanation:

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1. For the function f(x) = 3x + 1, find f(-2). (substitute -2 in for x)

puteri [66]

Answer:

f(-2) = -5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 3x + 1

f(-2) is x = -2

Step 2: Evaluate

Substitute in x: f(-2) = 3(-2) + 1
Multiply: f(-2) = -6 + 1
Add: f(-2) = -5

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3 years ago

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3 years ago

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STatiana [176]

Answer:

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Step-by-step explanation:

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2 years ago

( 4 + − 5 ) × ( 7 − − 3 )

SSSSS [86.1K]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A train slows down as it rounds a sharp horizontal turn, going from 92.0 km/h to 54.0 km/h in the 16.0 s that it takes to round

Mnenie [13.5K]

Calculation of centripetal acceleration(ac):

$a_c=\frac{v^2}{r}$

we can change our speed in terms of m/s

$v=54km/h=54*\frac{1000}{3600} m/s$

now, we can plug these values

$a_c=\frac{(54*\frac{1000}{3600})^2}{130}$

$a_c=1.73077m/s^2$

Calculation of tangential acceleration(at):

$a_t=\frac{\Delta v}{\Delta t}$

now, we can plug values

$a_t=\frac{(54-92)*\frac{1000}{3600} }{16}$

now, we can simplify it

$a_t=-0.65972 m/s^2$

Calculation of resultant acceleration:

$a=\sqrt{(a_c)^2+(a_t)^2}$

now, we can plug values

$a=\sqrt{(1.73077)^2+(-0.65972)^2}$

$a=1.85224m/s^2$ .............Answer

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3 years ago