Answer and explanation:
Given : A driving exam consists of 29 multiple-choice questions. Each of the 29 answers is either right or wrong. Suppose the probability that a student makes fewer than 6 mistakes on the exam is 0.26 and that the probability that a student makes from 6 to 20 (inclusive) mistakes is 0.53.
Let X be the number of mistake


To find : The probability of each of the following outcomes.
a) A student makes more than 20 mistakes
i.e. 





b. A student makes 6 or more mistakes
i.e. 


c. A student makes at most 20 mistakes
i.e. 
Using 'a' part 


d. Which two of these three events are complementary?
The complement of an event happening is the exact opposite: the probability of it not happening.
According to definition,
Option a and c are complementary events.
1. Put all values in decimals
0.222=0.222
1/5= 0.2
0.02= 0.02
2. Order the cakes from least to greatest
0.02, 0.2, 0.222
Hope this helps!
Part 1
<h3>Answer: 13</h3>
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Explanation:
We'll replace every copy of x with -3. Then use PEMDAS to simplify.
f(x) = -2x+7
f(-3) = -2(-3)+7
f(-3) = 6+7
f(-3) = 13
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Part 2
<h3>Answer: -11</h3>
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Explanation:
We work backwards in a sense compared to what part 1 did. Instead of finding f(x) based on x, we determine what x must be for a given f(x).
We'll replace f(x) with 29 and solve for x like so
f(x) = -2x+7
29 = -2x+7
-2x+7 = 29
-2x = 29-7
-2x = 22
x = 22/(-2)
x = -11
Note how if you replaced x with -11, we'd get,
f(x) = -2x+7
f(-11) = -2(-11)+7
f(-11) = 22+7
f(-11) = 29
which helps confirm we have the correct answer.