Question

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 ​ (2)=2x−1

Answer 1

Answer:

$9^{2x-1} = 2$

Step-by-step explanation:

According to the law of logarithm;

$If \ log_ab = x\\a^x = b$

Given

$\log_9\left(2\right)=2x-1$

Comparing with the original expression;

a = 9, b = 2 and c = 2x - 1

Substitute into the result indicinal expression;

$9^{2x-1} = 2$

This gives the required exponential equation