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3 years ago

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 (2)=2x−1

Mathematics

1 answer:

monitta3 years ago

7 0

Answer:

$9^{2x-1} = 2\\$

Step-by-step explanation:

According to the law of logarithm;

$If \ log_ab = x\\a^x = b$

Given

$\log_9\left(2\right)=2x-1$

Comparing with the original expression;

a = 9, b = 2 and c = 2x - 1

Substitute into the result indicinal expression;

$9^{2x-1} = 2\\$

This gives the required exponential equation

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Nadusha1986 [10]

A. He eats 1/8 a pound of candy each day.
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A. Since he ate 10 ounces in 5 days, you divide 10 by 5 to find he ate 2 ounces per day. Since there are 16 ounces in a pound that would be your denominator (bottom of fraction) and 2 would be the numerator (top of your fraction). You will get 2/16 which if you simplify (divide by 2) you get 1/8.

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3 years ago

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Choose the option with the proper number of sig figs

marishachu [46]

$\text{ 2 }\times10^8$

Explanation: $\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}$

let's break down the expression to get the final result:

$\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\ \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}$ $\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\ \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\ \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}$

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White raven [17]

Answer:

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Step-by-step explanation:

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Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 ​ (2)=2x−1

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 (2)=2x−1