3 years ago

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 (2)=2x−1

Mathematics

1 answer:

monitta3 years ago

7 0

Answer:

$9^{2x-1} = 2\\$

Step-by-step explanation:

According to the law of logarithm;

$If \ log_ab = x\\a^x = b$

Given

$\log_9\left(2\right)=2x-1$

Comparing with the original expression;

a = 9, b = 2 and c = 2x - 1

Substitute into the result indicinal expression;

$9^{2x-1} = 2\\$

This gives the required exponential equation

You might be interested in

Express the ratio 4:7 in the form n:1

Snowcat [4.5K]

Answer:

11:1

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Alik [6]

Answer:

Subtract by 5 on both sides.

Step-by-step explanation:

x+5 = -10. if you subtract both sides by 5, you will get x+5-5=-10-5, which can be simplified to x=-15.

3 0

3 years ago

Read 2 more answers

Would you set them equal to each other or 90 or 180. HELP ASAP

Ghella [55]

Answer:

Step-by-step explanation:

bc i said so

5 0

3 years ago

Simplify the difference.

sergey [27]

(D) -3w2<span> - 9w - 4
I hope this helped :)
</span>

6 0

2 years ago

Read 2 more answers

Write each expression below in radical form and compute the value without using a calculator.

gregori [183]

Assuming that an exponentiation sign is missing, all you need to know is that rational exponents work like this:

$a^{\frac{b}{c}}=\sqrt[c]{a^b}$

So, you have

$25^{\frac{5}{2}}=\sqrt{25^5}=\sqrt{(5^2)^5}=5^5$

And similarly,

$81^{\frac{7}{4}}=\sqrt[4]{25^7}=\sqrt[4]{(3^4)^7}=3^7$

5 0

2 years ago

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 ​ (2)=2x−1

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 (2)=2x−1