Answer:
Original Price = 160
Sale Price =40
Step-by-step explanation:
Let Original Price be x and Sale Price be y
y=1/4 of x (Equation 1)
x=120+y (Equation 2)
Put value of x from equation 2 in equation 1
y= (1/4)*(120+y)
y=120/4 + y/4
y-y/4=30
3y/4=30
y=30*4/3
y=40
Put value of y in Equation 2
x=120+40
x=160
A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.
From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.
Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.
Divide everything by 8 to isolate b and you get that b^2=9.
Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.
Now that we know that a=2 and b=3 just plug them into the equation.
-2(2)+3(3)=?
-4+9=?
5
Sorry about having to use this ^ symbol, the equation maker is not working.
9514 1404 393
Answer:
10) C 4/9
11) B 24
Step-by-step explanation:
10) The area ratio is the square of the ratio of side lengths. The ratio of side lengths is ...
RS/LM = 6/9 = 2/3
Then the area ratio is ...
(2/3)² = 4/9
__
11) Using the result of question 10, the area of ∆RST is ...
(4/9)(54 in²) = 24 in²
125 the common ratio es -6
What is the question you just said Can someone answer this what's the question