Which of the following groups of numbers are all prime numbers? A. 3, 11, 23, 31 B. 2, 3, 5, 9 C. 2, 5, 15, 19 D. 7, 17, 29, 49
Mekhanik [1.2K]
A because 9 is not prime in answer B, 15 is not prime in answer C, and 49 is not prime in answer D. So the correct answer is A.
Answer:
x = -2 y= -8 and 8
Step-by-step explanation:
Since there is an equal number of y's, they cancel out when subtracting. You can put either equation on top. You will get same answer.
<u>To find x:</u>
<u>If you do (3x - 2y = 10) - (5x + 2y = 6),</u> you will get -2x=4. Divide both sides by -2, and get x = -2.
<u>If you do (5x + 2y = 6) - (3x - 2y = 10)</u>, you will get 2x=-4.Divide both sides by 2, and get x = -2.
<u>To find y:</u>
Substitute -2 for x in either equation. It doesn't matter.
<u>For 3(-2) - 2y = 10:</u>
3(-2) - 2y = 10 ––Multiply
-6 - 2y =10 ––Add 6 to both sides to get y alone
-2y = 16 ––Divide by -2
y = -8
<u>For 5x + 2y = 6:</u>
5(-2) + 2y = 6 ––Multiply
-10 + 2y = 6 ––Add 10 to both sides to get y alone
2y = 16 ––Divide by 2
y = 8
Answer:
a) k = 5; (-10, -35)
Step-by-step explanation:
Given:
Co-ordinates:
Pre-Image = (-12,3)
After dilation
Image = (-60,15)
The dilation about the origin can be given as :
Pre-Image
where 
represents the scalar factor.
We can find value of for the given co-ordinates by finding the ratio of 
or 
co-ordinates of the image and pre-image.
For the given co-ordinates.
Pre-Image = (-12,3)
Image = (-60,15)
The value of 
or 
As we get 
for both ratios i.e of and co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.
To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.
Pre-Image
Image
Pre-Image Image
(Answer)
7b^2 - 19b + 10
(b - 2)(7b - 5)
b1 = 2 ; b2 = 5/7
Answer:
- 6°F
Step-by-step explanation:
Given :
Temperature at 6:00 = 15°F
Temperature dropped by 9°F by 8:00
Temperature by 8:00 = 15°F - 9°F = 6°F
Temperature dropped another 12°F by 11:00
Hence, Temperature at 11:00 will be :
6°F - 12°F = - 6°F
Temperature at 11:00 = - 6°F
