Question

List the 8 numbers between 4 and 40 in a sequence of 10 numbers a common difference

Answer 1

Answer:

8, 12, 16, 20, 24, 28, 32, 36

Step-by-step explanation:

the nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

a₁ is the first term and d the common difference

given a₁ = 4 and a₁₀= 40 , then

4 + 9d = 40 ( subtract 4 from both sides )

9d = 36 ( divide both sides by 9 )

d = 4

add d to each term to obtain the next term

4 + 4 = 8

8 + 4 = 12

12 + 4 = 16

16 + 4 = 20

20 + 4 = 24

24 + 4 = 28

28 + 4 = 32

32 + 4 = 36

the 8 terms between 4 and 40 are

8, 12, 16, 20, 24, 28, 32, 36