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Murrr4er [49]
3 years ago
7

Help me plzzzzzzzzzzzz

Mathematics
2 answers:
jasenka [17]3 years ago
6 0

Answer:

1. 10x^2 -4

2. 2a^5 + 5b

Step-by-step explanation:

1. Simplify 4(x^2 -1) to 4x^2 -4

then add that to 6x^2

2. 4a^5 - 2a^5 = 2a^5 and

4b+b = 5b

Alex_Xolod [135]3 years ago
4 0

Answer:

Step-by-step explanation:

6x² + 4(x² - 1) = 6x² + 4*x² - 4*1

           = 6x² + 4x² - 4    

            = 10x² - 4

4a⁵ - 2a⁵ + 4b +b = 2a⁵ + 5b

You have to add/ subtract the like terms

4a⁵ and 2a⁵ are like terms

4b and b are like terms

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Answer:

A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

∵ (hypotenuse)² = (3)² + (8)²

∴ (hypotenuse)² = 9 + 64

∴ (hypotenuse)² = 73

- Take √  for both sides

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- Round it to the nearest tenth of one inch

∴ hypotenuse = 8.5 inches

A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

∵ The hypotenuse of the right triangle whose legs are 3 and

   8 is 8.5 inches

∴ The length of the second leg is 8.5 inches

B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

∵ (3-dimensional diagonal)² = (5)² + (73)²

∴ (3-dimensional diagonal)² = 25 + 73

∴ (3-dimensional diagonal)² = 98

- Take √ for both sides

∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

∴ The length of the three-dimensional diagonal is 9.9 inches

<em>V.I.N: you can find the length of the  three-dimensional diagonal by using this rule → </em>d=\sqrt{l^{2}+w^{2}+h^{2}}<em> </em>

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For an object whose velocity in ft/sec is given by v(t) = −t2 + 2, what is its displacement, in feet, on the interval t = 0 to t
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Answer:

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Step-by-step explanation:

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Read 2 more answers
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