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tekilochka [14]

2 years ago

5

Helpplsplsplsplsplsplsigiveiraliset

1 answer:

den301095 [7]2 years ago

8 0

84. Each large salad needs 10 cherry tomatoes. So 6x10=60. Each small salad needs 6 cherry tomatoes. So 4x6=24. 60+24=84. Jorge needs 84 cherry tomatoes to make the salads.

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What is the following product?

devlian [24]

Answer: Last Option

$4x^5\sqrt[3]{3x}$

Step-by-step explanation:

To make the product of these expressions you must use the property of multiplication of roots:

$\sqrt[n]{x^m}*\sqrt[n]{x^b} = \sqrt[n]{x^{m+b}}$

we also know that:

$\sqrt[3]{x^3} = x$

So

$\sqrt[3]{16x^7}*\sqrt[3]{12x^9}\\\\\sqrt[3]{16x^3x^3x}*\sqrt[3]{12(x^3)^3}\\\\x^2\sqrt[3]{16x}*x^3\sqrt[3]{12}\\\\x^5\sqrt[3]{16x*12}\\\\x^5\sqrt[3]{2^4x*2^2*3}\\\\x^5\sqrt[3]{2^6x*3}\\\\4x^5\sqrt[3]{3x}$

6 0

3 years ago

A number y minus 12 is no more than −32.<br><br> The inequality is

Artyom0805 [142]

Answer:

y-12<-32

Step-by-step explanation:

just remember to underline the less than sign

3 0

2 years ago

Hey! i’ll give brainliest please help

myrzilka [38]

Answer:

The 4th answer

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The Cooking Club was making some pies to raise money for the school . The cafeteria made 2 pies and was cut into 6 pieces . How

Temka [501]

2? It says it in the question I think

5 0

3 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago