Answer:
6.72 g
Explanation:
Given data:
Mass of calcium chlorate = 13.8 g
Mass of oxygen produced = ?
Solution:
Chemical equation:
Ca(ClO₃)₂ → CaCl₂ + 3O₂
Number of moles of calcium chlorate:
Number of moles = mass / molar mass
Number of moles = 13.8 g/ 206.98 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of oxygen and calcium chlorate.
Ca(ClO₃)₂ : O₂
1 : 3
0.07 : 3×0.07=0.21 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.21 mol × 32 g/mol
Mass = 6.72 g
Answer:
There is a 1:1 neutralization reaction, so, number of moles:
0.085 l * 0.900 mol/ L = 0.0765 mol HCL
The heat produced: 0.0765 mol * -56.2 kJ/mol = -4.229 kJ (this is the heat of neutralization)
Change in temperature: The mass to use in the equation Q=cmT.
4229 J / (4.186 J/gC*170 g) = 6.042 C
Add to the initial temperature:
18.24 + 6.042 = 24.29 C°
Assuming that the number of mols are constant for both conditions:
Now you plug in the given values. V_1 is the unknown.
Separate V_1
V= 162.782608696 L
There are 2 sig figs
V= 160 L
The answer is Q because the red it's absorbed by object Q meaning only black will show
Answer:
2.77495 moles
Explanation:
Boron= 10.811g (according to periodic table)
