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IRISSAK [1]
3 years ago
10

PLEASE HELP ME!!!!!!!!

Physics
2 answers:
Ray Of Light [21]3 years ago
5 0

Answer:

I believe C

Explanation:

i never learned this sorry

DerKrebs [107]3 years ago
3 0
The answer is C) if I’m correct
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Nathan is standing 2 feet away from a plane mirror. Hiva is standing 5 feet further than
Viktor [21]

Answer:

They are standing 3 feet away from each other

Explanation:

If Nathan Is standing 2 feet away from the mirror. Then Hiva is standing 7 feet away from the mirror is she is standing 5 feet further than him. They are standing 3 feet away from each other.

3 0
3 years ago
Based on the Law of Conservation of Matter, what number should be placed in the box to balance the chemical equation below?
Rashid [163]

Answer:

2

Explanation:

Step 1: RxN

4Al + 3O₂ → Al₂O₃

Step 2: Balance RxN

We have 4 Al's and 6 O₂'s on the reactant side.

We need the same number of Al's and O₂'s on the product side.

4Al + 3O₂ → 2Al₂O₃

7 0
3 years ago
Read 2 more answers
From Doppler shifts of the spectral lines in the light coming from the east and west edges of the Sun, astronomers find that the
Gala2k [10]

Answer:

T= 37 day

Explanation:

To solve this exercise we will use the definition of angular velocity as the angular distance, which for a full period is 2pi between time.

    w = T / t

The relationship between angular and linear velocity is

    v = w r

    w = v / r

We substitute everything in the first equation

    v / r = 2π / t

    t = 2π r / v

Let's reduce to the SI system

    V = 2 km / s (1000m / 1km) = 2 10³ m / s

    r= R = 6.96 10⁸ m

Let's calculate

    t = 2π 6.96 10⁸/2 10³

    t = 3.2 10⁶ s

    T = t = 3.2 10⁶ s ( 1h/3600s) (1 day/24 h)

    T= 37 day

3 0
3 years ago
Which part(s) of a hair can be analyzed for nuclear DNA?
kiruha [24]
<span>hair follicle
should be your answer</span>
3 0
4 years ago
What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?
Marrrta [24]

Answer:

2.46\cdot 10^5 J

Explanation:

The enegy of a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck costant

c is the speed of light

\lambda is the wavelength of the photon

In this problem,

\lambda=486 nm=4.86\cdot 10^{-7}m

so the energy of one photon is

E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J

1 mole of photons contains a number of Avogadro of photons:

N_A = 6.022\cdot 10^{23}

therefore, the total energy of 1 mole of these photons will be

E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J

3 0
4 years ago
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