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2 years ago

What attribute do a rectangle, parallelogram, rhombus, and square ALL have in common?

Mathematics

1 answer:

Vikki [24]2 years ago

8 0

my answer has to be at least 20 letters.....

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Find the next two terms in this sequence. 4,8,-16,-32,64, [??],[??]

lubasha [3.4K]

I’m pretty sure this is the answer
128, -256

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2 years ago

What must be true and what letter is the answer?

Zanzabum

Answer:

4th one is correct for x/y

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3 years ago

What’s 6.5 inches times 4?

wolverine [178]

Answer:

your answer is 26 inches

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2 years ago

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If sec(theta) =25/24, find cot(theta) (Picture provided)

larisa [96]

Answer:

Step-by-step explanation:

By the definition,

$\sec \theta=\dfrac{\text{hypotenuse}}{\text{adjacent leg}}.$

If $\sec \theta=\dfrac{25}{24},$ we can consider right triangle with hypotenuse 25 un. and adjacent leg 24 un. By the Pythagorean theorem,

$\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{opposite leg}^2=25^2-24^2,\\ \\\text{opposite leg}^2=625-576,\\ \\\text{opposite leg}^2=49,\\ \\\text{opposite leg}=7\ un.$

So,

$\cot \theta=\dfrac{\text{adjacent leg}}{\text{opposite leg}}=\dfrac{24}{7}.$

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3 years ago

Read 2 more answers

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

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2 years ago