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3 years ago

{PLEASE HELP}

1 answer:

4 0

I'm not sure what method you are supposed to use to graph this. I would do it the following way although you can also change it to vertex form of the equation and graph it using (h,k) and "a".
The way I'd do it..

vertex (-b/2a , y)
-b/2a = -2
plug in this value for x to find the y coordinate.
-4 +8 -3 = 1
vertex (-2, 1)
the negative in front of the x^2 flips the parabola upside down

So you graph an upside down parabola at (-2,1). It's symmetrical, input easy to do points if needed like x=0 , x=-4

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4 years ago

(1) What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of negative 5/6 (all fractio

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[For (3) and (4) we need to solve for slope]

(3)
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3 years ago

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4 years ago

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