Which function below is decaying the fastest?
1 answer:
You might be interested in
Answer:
t = 0 at the start of the projection
Step-by-step explanation:
To solve this we need to find the distance between the 2 positions at any given time, then solve for the least distance
Let t be the time of the 2nd ball, so t + 1 is the time of the first ball
Let g be the gravitational acceleration, v be the horizontal velocity
the y coordinates of the first and 2nd balls
The x coordinates of the 1st and 2nd balls:
The distance between the 2 balls is
As both v and g are constant and cannot be changed, d is minimum when (2t + 1) is minimum, which happens only when t is minimum = 0