Find the volume of the cone. Round your answer to the nearest tenth if necessary. Use 3.14 for π.
2 answers:
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Answer:
24.24%
Step-by-step explanation:
In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12
Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.
or 0.2424 or 24.24%
Answer:
Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is .
Step-by-step explanation:
From the given question, the bag contains;
$1 bill = 7
$5 bill = 1
$10 bill = 3
$20 bill = 2
Total number of bills in the bag = 13
Pulling a bill at random, the bills would have an expected value as follows:
For $1 bill, the expected value =
For $5 bill, expected value =
For $10 bill, expected value =
For $20 bill, the expected value =
Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is .