X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:
X=3.1
(4•3.1)+(4•3.1)
Step-by-step explanation:
4 of 6.2 is equal to 24.8
4•(6+0.2) = 24.8
4•3.1=12.4•2=24.8
12.4+12.4=24.8
(4x)+(4×)=24.8
We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots
The least common denominator of 5/12 and -9/16
The answer is 48.
Now, we have to change the numerators also to make this a equal fraction to the first ones we had.
5*4 = 20
12*4 = 48
20/48
-9*3 = -27
16*3 = 48
-27/48
<span>ax(d) = absolute value of the difference = ax(a-b).
d(ax) = difference of the absolute value = ax(a) - ax(b).
ax(a-b) = absolute value of (a - b).
ax(a) - ax(b) = absolute value of (a) minus absolute value of (b).
Hope this works :)</span>
