What is the surface area of the given figure? and how did you find the answer?

My Notes The displacement from equilibrium of an oscillating weight suspended by a spring is given by y(t) = 1 4 cos(5t) where y

ikadub [295]

Answer:

y(0) = 0.25 feet

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

Step-by-step explanation:

We are given the following information in the question:

The displacement from equilibrium of an oscillating weight suspended by a spring =

$y(t) = \displaystyle\frac{1}{4} \cos(5t)$

where y is the displacement in feet and t is the time in seconds.

Here, cos is in radians.

1) t = 0

$y(0) = \displaystyle\frac{1}{4} \cos(5(0)) = \frac{1}{4} \cos(0) = \frac{1}{4}(1) = \frac{1}{4}$

y(0) = 0.25 feet

2) t = $\frac{1}{4}$

$y(\displaystyle\frac{1}{4}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{4})) = \frac{1}{4} \cos(1.25) = \frac{1}{4}(0.31532236) =0.07883059$

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

3) t = $\frac{1}{2}$

$y(\displaystyle\frac{1}{2}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{2})) = \frac{1}{4} \cos(2.5) = \frac{1}{4}(-0.80114362) = -0.200285905$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

The negative sign indicates the opposite direction of displacement.

3 0

3 years ago

I need to get 2 answered please help it’s with mean, median and mode

Marat540 [252]

They are all averages

mean=average 4+6=10, 10 divded by 2= 5, the mean is 5

median= middle number, 5 6 7, 6 is the median
mode= most repeated number, so 4,4,4,4,4,4,4,5.5,6 4 is the mode

7 0

3 years ago

2. In your own words, explain HOW to find the standard deviation of this data set. (20 points) 3. What does the standard deviati

Ket [755]

Answer:

$\sigma = 11.28$ --- Standard deviation

Step-by-step explanation:

Given

See attachment for graph

Solving (a): Explain how the standard deviation is calculated.

<u>Start by calculating the mean</u>

To do this, we divide the sum of the products of grade and number of students by the total number of students;

i.e.

$\bar x = \frac{\sum fx}{\sum f}$

So, we have:

$\bar x = \frac{50 * 1 + 57 * 2 + 60 * 4 + 65 * 3 +72 *3 + 75 * 12 + 77 * 10 + 81 * 6 + 83 * 6 + 88 * 9 + 90 * 12 + 92 * 12 +95 * 2 + 99 * 4 + 100 * 5}{1 + 2 + 4 + 3 +3 + 12 + 10 + 6 + 6 + 9 + 12 + 12 +2 + 4 + 5}$

$\bar x = \frac{7531}{91}$

$\bar x = 82.76$

Next, calculate the variance using the following formula:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f}$

i.e subtract the mean from each dataset; take the squares; add up the squares; then divide the sum by the number of dataset

So, we have:

$\sigma^2 = \frac{1 * (50 - 82.76)^2 +...................+ 5 * (100 - 82.76)^2}{91}$

$\sigma^2 = \frac{11580.6816}{91}$

$\sigma^2 = 127.26$

Lastly, take the square root of the variance to get the standard deviation

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{127.26}$

$\sigma = 11.28$ --- approximated

<em>Hence, the standard deviation is approximately 11.28</em>

Considering the calculated mean (i.e. 82.76), the standard deviation (i.e. 11.28) is small and this means that the grade of the students are close to the average grade.

8 0

3 years ago

What sets does the fraction -4/9 belong to?

atroni [7]

Real number, rational number

6 0

3 years ago

PLEASE HELP

antiseptic1488 [7]

Answer:

The principal amount is 5000 dollars = 3, 70,000 rupees (5000 dollars x 74 Rupees)

Rate = 2.5%

Time = 1 year

Now, on putting the values given in the formula

S.I.= 9,250 Rupees

Now we convert it into dollars by diving 9,250 rupees by 74 rupees.

We get,

9250/74 = 125 dollars

Step-by-step explanation:

3 0

2 years ago

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