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3 years ago

Algebra 2 Solve each equation to the nearest thousand Help pls

Mathematics

1 answer:

borishaifa [10]3 years ago

5 0

I don’t understand your question, can you give more details please

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Charlie is standing 45 feet from the base of 100 foot tall tree. What is the angle of elevation from him to the kite stuck on to

galben [10]

Hey. Let me help you on this one.

In order for us to solve this problem easier, let's break it apart. We can also graph the triangle so we get visual of this problem.

I drew a quick graph for you to easier understand this question. As you can see, Charlie is standing below the tree 45 feet from it, and we need to find the unknown angle measure.

Let's form a SOHCAHTOA function which you have probably already learned in your Geometry course.

First of all let's identify our sides. The side opposite of the right triangle is a Hypotenuse, and the side that's 45 feet is adjacent, since it's adjacent to the unknown angle.

We know that we need to use $Cos$ (Cosine) with negative power to it in order to solve this question, since we are looking for the unknown angle measure.

Let's form the function which $Cos$ , Hypotenuse, and Adjacent side.

$Cos^{-1} =45/100$

Now, let's solve the left part of this function

$
Cos^{-1} =0.45$

Awesome. You will need to use your calculator for this part. Find the value of 0.45 when negative Cosine is used on it.

$Cos^{-1} =0.45$
$63.25631605$

Awesome. Let's round this number to the closest tenth

$63.3$ is the rounded value we have discussed below.

Answer: 63.3 degrees is the unknown measure of the angle

5 0

3 years ago

Which equation is a direct variation function?<br> O y=x<br> O y = x + 2<br> O y=&<br> Oy=4

LiRa [457]

The answer is B , y= x + 2

8 0

3 years ago

Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (

IrinaVladis [17]

Answer:

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14 and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = $\dfrac{9+9}{2}$

median = $\dfrac{18}{2}$

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = $\dfrac{12+13}{2}$

Median = $\dfrac{25}{2}$

Median = 12.5

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = Q3 - Q1

The interquartile range = 12.5 - 9

The interquartile range = 3.5

7 0

3 years ago

The sum of 2a and 3b

slava [35]

The sum of 2a and 3b:

2a + 3b

7 0

3 years ago

If you plotted the points in the table and connected

castortr0y [4]

Answer:

U shaped.

Step-by-step explanation:

When x = 0 , f(x) = 6

when x =1 yf(x) = 0

when x = 2 f(x) = -2

x = 3 f(x) = 0

x = 4 f(x) = 6.

So the graphs falls from the left and rises to the right in the form of a U.

You can draw a rough graph to confirm this.

3 0

3 years ago