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We already solve for the B or area of the triangular base which was 5.25cm².
There are 2 triangular faces in the prism so 5.25cm² x 2 = 10.50cm²
There are 3 rectangular face in the prism, we need to get the area of each.
area of a rectangle = length x width
rectangle 1: 5 cm x 4 cm = 20 cm²
same dimension with rectangle 2. so, area is 20 cm² also
rectangle 3: 5 cm x 2.8 cm = 14 cm²
let us all add up the area of each surface.
2 triangle = 10.50 cm²
3 rectangles = 20 cm² + 20 cm² + 14 cm² = 54 cm²
10.50 cm² + 54 cm² = 64.50 cm²
Answer: c. getting heads on a coin toss and rolling a 5 on a die
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given
Length of rectangle is 
Perimeter must be greater than 40 ft
Suppose l and w be the length and width of the rectangle
So, the smallest width can be
For this, we need to find the lowest common multiple of 12 and 15....
common multiples of 12 : 12,24,36,48,60
common multiples of 15 : 15,30,45,60
LCM = 60
the caller that will be the first to win both is the 60th caller
The answer is C.
Here's why, nPr = n!/(n-r)!. Plug in 7 for n and 3 for r. And you get 7!/(7-3)!.
Thus, 7!/4! = (7*6*5*4*3*2*1)/(4*3*2*1), which simplifies to 7*6*5 = 210
