Question

(QUICK) Based on difference in electronegativities between atoms, which is the most polar bond pair? H — S H — Cl H — O H — F

Answer 1

Answer: Option (d) is the correct answer.

Explanation:

It is known that more is the electronegativity difference between the combining atoms, more polar is the bond formed by them.

Therefore, electronegativity difference for the given species is as follows.

Electronegativity of H = 2.2

Electronegativity of S = 2.58

Electronegativity of Cl = 3.16

Electronegativity of O = 3.44

Electronegativity of F = 3.98

Hence, electronegativity of H-S = 2.58 - 2.2 = 0.38

Electronegativity of H-Cl = 3.16 - 2.2 = 0.96

Electronegativity of H-O = 3.44 - 2.2 = 1.24

Electronegativity of H-F = 3.98 - 2.2 = 1.78

Thus, electronegativity difference is maximum for H-F.

Therefore, we can conclude that H-F is the most polar bond pair.

Answer 2

First, you need to have a periodic table that contains the electronegativities values. once you have them, you just need to subtract the values of the atoms and each bond. I have attached a table with these values. also, it does not matter then order in which you subtract them because they are always positive values. even though you get negative values in your calculator, just make it positive.

H-S----> 2.1 - 2.5= 0.4
H-Cl---> 2.1 -3.0=0.9
H-O---> 2.1- 3.5= 1.4
H-F----> 2.1 - 4.0= 1.9

HF is the most polar because it has the highest electronegativity difference.