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Musya8 [376]
4 years ago
5

When a sound source approaches you, the pitch you hear is

Chemistry
1 answer:
IgorC [24]4 years ago
7 0
Higher <span>C. higher than when the source is stationary</span>
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Which of the following choices best explains why glaciers move?
irinina [24]
D. Should be correct- the other ones don’t make sense
4 0
3 years ago
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CH4 + 202 → CO2 + 2H2O<br> How many moles O2 needed to produce 4 moles of H2O?
shepuryov [24]
<h3>Answer:</h3>

4 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   4 mol H₂O

[Solve]   x mol O₂

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol H₂O → 2 mol O₂

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                    \displaystyle 4 \ mol \ H_2O(\frac{2 \ mol \ O_2}{2 \ mol \ H_2O})
  2. Multiply/Divide:                          \displaystyle 4 \ mol \ O_2
7 0
3 years ago
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Yasmins teacher tells her that the solubility of salt is 360g/L at room temperature (25C) . How can yasmin make an unsaturated s
OLga [1]
35c that’s all I know to be honest
6 0
3 years ago
What is the pH of 500 mL of water after the addition of 1 mL of 2M NaOH?
Fudgin [204]

Answer:

pH = 11.60

Explanation:

When we add a base, we are increasing [OH⁻], so the pH will be totally basic.

pH of water = 7

Basic pH > 7

We are adding 2 M . 1 mL = 2 mmoles

2 mmoles of OH⁻ are contained in 501 mL of total volume.

[OH⁻] = 2 mmol / 501 mL =  3.99×10⁻³ M

- log 3.99×10⁻³ M = 2.39 → pOH

pH = 14 - pOH → 11.61

Water equilibrium

2H₂O  ⇄  H₃O⁺   +  OH⁻          Kw = 1×10⁻¹⁴

NaOH  →  Na⁺   +  OH⁻

8 0
3 years ago
Catalytic converters made of palladium (pd) reduce automobile pollution by catalyzing the reaction between unburned hydrocarbons
Doss [256]
Unburned hydrocarbon on reacting with oxygen undergoes combustion reaction. However, the activation energy of this reaction is significantly high. When a catalyst like Pd is added to the reaction system, it provides active sites for the reaction to occur. It acts are a heterogeneous catalyst. It is pertinent of note that catalyst is refereed as heterogeneous, when it exist in different phase as compared to reactant and products. In present case, reactants and products are in gas phase, while catalyst is in solid phase. Due to availability of larger surface area at active site of Pd, activation energy of reaction decreases and decrease in activation energy favors higher reaction rates. 
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4 years ago
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