I believe that it is A. If you remember in lesson 03.03 it gave multiple examples of things that support the continental drift theory. One of them was fossils of the same organisms found in different continents.
Answer:
Natural gas, emitting fewer harmful chemicals into the atmosphere than other fossil fuels, can help to mitigate some of these environmental issues. These issues include: Greenhouse Gas Emissions. Smog, Air Quality and Acid Rain
Explanation:
It is a completely true statement that a <span>base increases the OH- ion concentration of water. The correct option among the two options that are given in the question is the first option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>
Answer:
<h3>The answer is 3.0 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
![density = \frac{mass}{volume} \\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7Bmass%7D%7Bvolume%7D%20%5C%5C)
From the question
mass = 15 g
volume = 5 mL
We have
![density = \frac{15}{5} \\](https://tex.z-dn.net/?f=density%20%3D%20%20%5Cfrac%7B15%7D%7B5%7D%20%20%5C%5C%20)
We have the final answer as
<h3>3.0 g/mL</h3>
Hope this helps you
Answer:
All of the above.
Explanation:
In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.
When a solution is non ideal then it shows positive or negative deviation.
Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is
and vapour pressure of component B is
.
= Vapour pressure of component A in pure form
= Vapour pressure of component B in pure form
=Mole fraction of component A
=Mole fraction of component B
The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.
,![P_B>P^0_B\cdot x_B](https://tex.z-dn.net/?f=P_B%3EP%5E0_B%5Ccdot%20x_B)
Therefore, ![P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B](https://tex.z-dn.net/?f=P_A%2BP_B%20%3EP%5E0_A%5Ccdot%20x_A%2BP%5E0_B%20%5Ccdot%20x_B)
Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.
Hence, option a,b,c and d are true.