Which pair of atoms has the highest electronegativity difference? Na-F Ca-F H-F C-F F-F

Chemistry

2 answers:

neonofarm [45]3 years ago

5 0

Answer: Na-F has the highest electronegativity difference.

Explanation: Electronegativity is the measure of how strongle an atom holds the electrons. The highest electronegative atom is Fluorine.

Electronegativity of Sodium = 0.93

Electronegativity of Calcium = 1

Electronegativity of Hydrogen = 2.1

Electronegativity of Carbon = 2.55

Electronegativity of Fluorine = 3.98

Electronegativity difference in the following compounds:

Electronegativity difference in Na-F = 3.98 - 0.93 = 3.05

Electronegativity difference in Ca-F = 3.98 - 1 = 2.98

Electronegativity difference in H-F = 3.98 - 2.1 = 1.88

Electronegativity difference in C-F = 3.98 - 2.55 = 1.43

Electronegativity difference in F-F = 3.98 - 3.98 = 0

From the above calculations, it is visible that the highest electronegativity difference is present in Na-F.

From all the compounds, it is clearly seen that sodium can loose the electrons easily and is most electropositive and fluorine is the most electronegative element.

babunello [35]3 years ago

3 0

The answer is Na-F. The F has highest electronegativity among these elements. So we need to find the element with smallest electronegativity. And this element is Na.

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