- P2H2 Oxidation State - Diphosphene
P2H2 has an oxidation number of +1. In P2H2, the oxidation
number of H is -1
- H2C2O4 Oxidation State - Oxalic Acid
C has an oxidation number of +3 in H2C2O4. O has an oxidation
number of -2 in H2C2O4. H2C2O4 has an oxidation number of +1.
- CrO2 Oxidation State - Chromium(IV) Oxide
CrO2 has an oxidation number of +4.
<h3>Explain oxidation?</h3>
The oxidation state, also known as the oxidation number, is an atom's hypothetical charge if all of its bonds to other atoms were fully ionic.
The sum of the oxidation states of all the atoms in an ion equals the ion's charge.
A substance's more electronegative element is given a negative oxidation state. The one that is less electronegative is given a positive oxidation state.
To learn more about oxidation refer to :
brainly.com/question/27239694
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<u>Answer:</u> The equilibrium constant for the given reaction is 0.8
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of the products raised to the power its stoichiometric coefficients to the concentration of reactants raised to power its stoichiometric coefficient. It is represented as 
For the general equation:
The equilibrium constant is represented as:
![K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
For the given chemical equation:
for this equation is given by:
![K_c=\frac{[H_2O][CO]}{[H_2][CO_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2O%5D%5BCO%5D%7D%7B%5BH_2%5D%5BCO_2%5D%7D)
Concentration at equilibrium of
Putting values in above equation, we get:
Hence, the equilibrium constant for the given chemical reaction is 0.8
Dependent variable. the independent is non dependent of the variable.
What exactly is the question
