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Andre45 [30]
3 years ago
7

What is the correct way to write 1,550,000,000 in scientific notation? 1.55 Times. 109 1.55 Times. 1010 15.5 Times. 108 15.5 Tim

es. 109
Chemistry
2 answers:
Citrus2011 [14]3 years ago
8 0
The correct way is 1.55 x 10^9
Phoenix [80]3 years ago
3 0

Answer:

A

Explanation:

its a bruh

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As a reaction proceeds, the ratio between the rate of consumption of reactant and the rate of formation of product:
wariber [46]

Answer:

Depends on the reaction.

Explanation:

Hello,

In this case, the answer is depends on the reaction since the ratios between the rates of both consumption and formation depend upon the stoichiometric coefficients in the chemical reaction. For instance, for the reaction:

A -> 2B

The relationship is:

\frac{1}{-1}r_A =\frac{1}{2} r_B

Therefore, we can see that the rate of consumption of A half the rate of formation of B, but is we consider the following chemical reaction:

2A -> B

The relationship is:

\frac{1}{-2}r_A =\frac{1}{1} r_B

Therefore we can see that the rate of consumption of A doubles the rate of consumption of B.

Best regards.

3 0
3 years ago
PLEASE PLEASE HELP
Elina [12.6K]

add it up maybe?

Explanation:

4 0
4 years ago
Which is given as an example for how the paleozic supercontinent ice cap melted?
serg [7]

 

An example for how the Paleozic supercontinent ice cap melted is through plants dying off, which in turn, increased the greenhouse effect.

 

To add, <span>the trapping of the sun's warmth in a planet's lower atmosphere due to the greater transparency of the atmosphere to visible radiation from the sun than to infrared radiation emitted from the planet's surface is called the greenhouse effect.</span>

6 0
4 years ago
Need little help pls
Julli [10]

Answer:

0.354 molal

Explanation:

The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).

Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( 10^{-3} ) and kilo- denotes a factor of one thousand ( {10}^3 ),

1.202 \ \frac{g}{mL} \ = \ 1.202 \ \frac{g}{(10^{-3}) L} \ = \ 1.202 \ \frac{{10}^3g}{L} \ = \ 1.202 \ \frac{kg}{L}.

To calculate the corresponding molality of the solution, the formula

Molality \ (mol/kg) \ = \ \frac{Molarity \ (mol/L)}{Density \ (kg/L)} is used.

Therefore,

Molality \ = \ \frac{0.426 \ mol/L}{1.202 \ kg/L} \ = \ 0.354 \ mol/kg \ \ (3 \ s.f.)

4 0
3 years ago
1. Balance the following decomposition of NaHCO3.<br> NaHCO3 →<br> Na2CO3 +<br> CO2 +<br> H2O
Vika [28.1K]

Answer: Count all the atoms on each side of the chemical equation once you know how how many of each type of atom.

Explanation:you can only change the coefficients (the number in front of the atom )

6 0
3 years ago
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