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3 years ago

One or two please answer

Chemistry

2 answers:

hichkok12 [17]3 years ago

8 0

Answer:

taken away

Explanation:

bc you have to take away more heat to make it into a solid

wlad13 [49]3 years ago

4 0

The answer is number one which is added

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2C2H2 + 5O2 → 4CO2 + 2H2O

Mumz [18]

Answer:

d. Two moles of carbon dioxide were produced from this reaction

Explanation:

The given chemical reaction can be written as follows;

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

From the above chemical reaction, we have;

Two moles of C₂H₂ reacts with five moles of O₂ to produce four moles of CO₂ and two moles of H₂O

We have;

One mole of C₂H₂ will react with two and half moles of O₂ to produce <em>two moles of CO₂</em> and one mole of H₂O

Therefore, in the above reaction, when one mole of C₂H₂ is used, two moles of CO₂ will be produced.

8 0

3 years ago

Studio

coldgirl [10]

Answer:

0.895 g/mL

Explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

$2.763 lb \times \frac{453.59 g}{1lb} = 1,253g$

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

$5.93cup \times \frac{236.59mL}{1cup} = 1.40 \times 10^{3} mL$

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

$\rho = \frac{m}{V} = \frac{1,253g}{1.40 \times 10^{3}mL } = 0.895 g/mL$

4 0

3 years ago

At equilibrium, the concentrations in this system were found to be [N21 O20.200 M and [NO]0.500 M. N2(8) 02e) 2NO(g) If more NO

erastovalidia [21]

Answer : The concentration of $NO$ at equilibrium is 0.9332 M

Solution : Given,

Concentration of $N_2$ and $O_2$ at equilibrium = 0.200 M

Concentration of $N_2$ and $O_2$ at equilibrium = 0.500 M

First we have to calculate the value of equilibrium constant.

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

$K_c=\frac{(0.500)^2}{(0.200)\times (0.200)}$

$K_c=6.25$

Now we have to calculate the final concentration of NO.

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initially 0.200 0.200 0

.800

At equilibrium (0.200-x) (0.200-x) (0.800+2x)

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

$K_c=\frac{(0.800+2x)^2}{(0.200-x)\times (0.200-x)}$

By solving the term x, we get

$x=2.6\text{ and }-0.0666$

From the values of 'x' we conclude that, x = 2.6 can not more than initial concentration. So, the value of 'x' which is equal to 2.6 is not consider.

And the negative value of 'x' shows that the equilibrium shifts towards the left side (reactants side).

Thus, the concentration of $NO$ at equilibrium = (0.800+2x) = 0.800 + 2(0.0666) = 0.9332 M

Therefore, the concentration of $NO$ at equilibrium is 0.9332 M

5 0

4 years ago

A solution has a Ph of 3.73. The pOH of this solution is?

ollegr [7]

PH + pOH = 14.
So, subtract 3.73 from 14.

The pOH is 10.27 :)

7 0

3 years ago

Due today will give brain list .

fredd [130]

1. Heart

2. Circulatory system

3. The circulatory system delivers oxygen and nutrients to cells and take away water .

4. Your heart is a muscle and it’s job is to pump blood throughout your circulatory system.

Hope this helps :)

Have a great day!

7 0

3 years ago