A 70 kg object is on a table in static equilibrium. What is the support (normal) force the table exerts on the box
1 answer:
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The magnitude of the air drag when the object is traveling at terminal velocity is C. 850 Newtons
Explanation:
There are only two forces acting on the object here:
- The force of gravity, of magnitude , acting downward
- The air drag, , acting upward
Therefore, the equation of motion for the object is
where m is the mass of the object and a its acceleration.
The object in this problem is traveling at terminal velocity: this means that the acceleration is zero, so
a = 0
Therefore the equation becomes
which means that the magnitude of the air resistance is equal to the magnitude of the force of gravity:
Learn more about acceleration and Newton laws of motion here:
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