Answer:
a)W=8.333lbf.ft
b)W=0.0107 Btu.
Explanation:
<u>Complete question</u>
The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.
Solution
Preload = F₀=0 lbf
Spring constant k= 200 lbf/in
Initial length of spring x₁=0
Final length of spring x₂= 1 in
At any point, the force during deflection of a spring is given by;
F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.
Change to lbf.ft by dividing the value by 12 because 1ft=12 in
100/12 = 8.333 lbf.ft
work required to compress the spring, W=8.333lbf.ft
The work required to compress the spring in Btu will be;
1 Btu= 778 lbf.ft
?= 8.333 lbf.ft----------------cross multiply
(8.333*1)/ 778 =0.0107 Btu.
Answer:
Explanation:
Let say the ball is projected at an angle with horizontal
So here two components of the velocity of the ball is given as
now the displacement in x direction is given as
in y direction it is given as
now from above two equations
Answer:
39 miles
Explanation:
we will make your house to be the central point in the four cardinal points.
Please follow the diagram on the attachment to get the movement clearly.
First, you move to a dry cleaners 12miles east of your house, and then to a grocery store 15miles west of your house.
This means you must have moved back to your house before going to the grocery which is 15miles west of your house.
so to and fro from your house to dry cleaners = 12*2 = 24 miles.
Then the total distance you cover will be = 24 +15 = 39 miles
Answer:
The moon and sun cause tidal bulges to move around the planet in perfect sync and unison.
Explanation:
However, do not consider these to be large oceans of water moving in relation to continents. Only the fluctuations in water level—the water's surface profile—follow the moon's and sun's positions in the sky.