Answer:
F = 2.113 x 10⁵ N
Explanation:
First we need to calculate the deceleration of the driver by using 3rd equation of motion:
2as = Vf² - Vi²
where,
a = deceleration = ?
s = distance = 5 cm = 0.05 m
Vf = Final Velocity = 0 m/s
Vi = Initial Velocity = 18 m/s
Therefore,
2a(0.05 m) = (0 m/s)² - (18 m/s)²
a = (- 324 m²/s²)/0.1 m
a = - 3240 m/s²
where, negative sign represents deceleration
From Newton's Second Law of Motion:
F = ma
F = (65 kg)(-3240 m/s²)
F = - 2.106 x 10⁵ N
So, he closest answer is:
<u>F = 2.113 x 10⁵ N</u>
t1 = √2h1/g = √2*0.5/9,8 = 0.319 sec
t2 = √2h2/g = √2*1.0/9,8 = 0.451 sec
In which t = times for the vertical movement
h = height
g= gravity (we use standardized measurement of 9.8)
d1 = 1*0.319 = 0.319 m
d2 = 0.5*0.451 = 0.225 m
in which d = Horizontal distance
ratio
= di : d2
= 0.319 : 0.225
= 3.19 : 2.25
Answer:
0.6
Explanation:
Angular acceleration is equal to Net Torque divided by rotational inertia, which is the rotational equivalent to Newton’s 2nd Law. Therefore, angular acceleration is equal to 3.6/6 which is 0.6. Hope this helped!
You should just ask the wave
