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Rzqust [24]
3 years ago
12

What is the chemical formula for magnesium sulfide?

Physics
1 answer:
ira [324]3 years ago
4 0

Answer:

MgS

Explanation:

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Why do moving back and forth, and moving in a circle look the same on a graph of position versus time?
pentagon [3]

Answer:

  one dimension of motion on a circle is "back and forth"

Explanation:

Whether the position graphs look the same or not is a function of the acceleration (and velocity), and how position is measured.

For a circle centered at the origin, uniform motion around the circle will be equivalent to sinusoidal motion in the x- or y-directions. So, that motion is equivalent to sinusoidal motion "back and forth", however it may be generated.

The "back and forth" motions of a piston in a cylinder (connected to a crankshaft), and of a pendulum, are almost sinusoidal, but not quite. Their position graphs will differ slightly from the graph of position of an object moving around a circle.

__

On the other hand, if the circular motion is plotted as the length of the radius versus time, it will be a constant -- not "back and forth" at all.

__

In short, plots of similar motion will look similar.

3 0
3 years ago
When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.47 mm .What is the flea's acceleration during the j
garri49 [273]
We can use kinematics here if we assume a constant acceleration (not realistic, but they want a single value answer, so it's implied). We know final velocity, vf, is 1.0 m/s, and we cover a distance, d, of 0.47mm or 0.00047 m (1m = 1000mm for conversion). We also can assume that the flea's initial velocity, vi, is 0 at the beginning of its jump. Using the equation vf^2 = vi^2 + 2ad, we can solve for our acceleration, a. Like so: a = (vf^2 - vi^2)/2d = (1.0^2 - 0^2)/(2*0.00047) = 1,064 m/s^2, not bad for a flea!
8 0
3 years ago
Read 2 more answers
Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by 0.1
ludmilkaskok [199]

Answer:

1.189eV

Explanation:

The electric potential energy is the potential energy that results from the Coulomb force and is associated with the configuration of two or more charges. For an electron in the presence of an electric field produced by a proton, the electric potential energy is defined as:

U=\frac{kq_{e}q_{p}}{r}

where  q_{e} is the electron charge, q_{p} is the proton charge, r is the separation distance between the charges and k is the coulomb constant.

Knowing this, we can calculate how much electric potential energy was lost:

\Delta U=U_{f}-U{i}\\\Delta U=\frac{kq_{e}q_{p}}{r_{f}}-\frac{kq_{e}q_{p}}{r_{i}}\\\Delta U=kq_{e}q_{p}(\frac{1}{r_{f}}-\frac{1}{r_{i}})\\\Delta U=(8.99*10^9\frac{Nm^2}{C^2})(-1.60*10^{-19}C)(1.60*10^{-19}C)(\frac{1}{0.105*10^{-9}m}-\frac{1}{0.115*10^{-9}m})\\\Delta U=1.90*10^{-19}J*\frac{6.2415*10^{18}eV}{1J}=1.189eV

5 0
4 years ago
Describe the path of an electrical impulse as it moves through a neuron
maksim [4K]

Answer & Explanation:

The nerve impulses start in the dendrites then moves down the axon starting in the axon. Nerve impulses speed up the myelin sheath. Then through the nodes of ranvier speeding up action potential then at the axon terminal the electrical impulse goes through the synapse through electrical then chemical with neurotransmitters and electrical again back to a dendrite.

8 0
3 years ago
If a rock falls for 5 seconds near the surface of the earth and with no air friction, it will reach a velocity of
sukhopar [10]

Answer: -49m/s.

Explanation:

As the rock only falls, we will assume that the initial vertical velocity is zero.

We neglect the air friction, so the only force acting on the rock is the gravitational force, this means that the acceleration is -g = -9.8m/s^2.

Then we can write:

a(t) = -9.8m/s^2

To write the velocity of the rock, we must ingrate over time and get:

v(t) = (-9.8m/s^2)*t + v0

where v0 is the initial vertical velocity, and as we said above, v0 = 0m/s

Then the vertical velocity as a function of time is:

v(t) = (-9.8m/s^2)*t

Now, the question is:

"...If a rock falls for 5 seconds near the surface of the earth and with no air friction, it will reach a velocity of..."

Then we need to evaluate the velocity equation in t = 5 seconds.

v(5s) = (-9.8m/s^2)*5s = -49m/s.

3 0
3 years ago
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