You would use order of operations: PEMDAS
P(parenthesis) E(exponents) MD(multiplication/division) AS(addition/subtraction)
with MD and AS order doesnt matter.
8(5-32) you would start with inside the Parenthesis for "P" so (5-32)=(-27)
next you would go to the E but because you dont have an exponent you go to the next step with is the "MD" you have multiplication so next would be 8(-27) and 8 multiplied by -27 is: 8(-27)= -216
ANSWER: -216
The answer is A hope this helps
Answer:
Tommy Thomas's tankard holds 160ml when it is one-quarter full.
Step-by-step explanation:
When Tommy's tankard holds 480ml when it's one-quarter empty. There are three other quarters in the tankard. So, you would divide 480 by 3 to see how much is in each of the other 3 quarters. The answer comes down to 160ml per quarter, which equals one-quarter full.
Answer:

Step-by-step explanation:
<u>Properties of Logarithms</u>
We'll recall below the basic properties of logarithms:

Logarithm of the base:

Product rule:

Division rule:

Power rule:

Change of base:

Simplifying logarithms often requires the application of one or more of the above properties.
Simplify

Factoring
.

Applying the power rule:

Since


Applying the power rule:

Applying the logarithm of the base:
