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uysha [10]
2 years ago
11

If you were to solve the equation x+14=22, what steps would you take to solve this equation?​

Mathematics
1 answer:
inessss [21]2 years ago
7 0

subtract 14 from 22 to isolate the variable

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Please simplify each expression for 18, 20, and 21
NeX [460]
The answer to the questions

5 0
3 years ago
Mrs. Bautista invested Php2700.00 part at 8% and the rest at 11% .How musch did she invest at each rate if her total annual inco
Margarita [4]

Answer:

The answer to the question is

She invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

Step-by-step explanation:

To solve the question we note that

Simple interest is given by \frac{P*R*T}{100} where

P= Principal, R = Rate and T = Time

If we call the first part P₁, T₁,  and R₁ and the second part

P₂, T₂,  and R₂

Then {P_1*(1+R_1*T_1}) +{P_*(1+R_2*T_2})  = 2460.00

= 2700×0.08×1 + P₂×0.11×1 = 2460  which gives

2244÷0.11 = P₂ or P₂ = Php 20,400.00

That is she invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

5 0
3 years ago
Two storage sheds ye to have to same area. One is square and one is rectangular. The rectangular shed is 2 meters wide and 8 met
natima [27]
8 x 2 = 16

Square root of 16 = 4

One side of the square is 4 meters.
5 0
3 years ago
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
Charra [1.4K]

Answer:

the download cost for a song is $1 and $11 for a movie

Step-by-step explanation:

According to the questions, the following equations are as follows:

Let us assume the song be x

And, the movies be y

So,

20x + 13y = $163.........(i)

13x + 13y = $156........(ii)

Now solve substract second equation from the first equation

7x = $7

x = $1

And the y value is

20 + 13y = $163

13y = $163 - $20

13y = $143

y = $11

Hence, the download cost for a song is $1 and $11 for a movie

5 0
3 years ago
Juno calculated the area of a square to be 4/9 square yard. Which shows the side length of the square?
Stella [2.4K]
\bf \textit{area of a square}\\\\
A=s^2~~
\begin{cases}
s=side's~length\\
--------\\
A=\frac{4}{9}
\end{cases}\implies \cfrac{4}{9}=s^2
\\\\\\
\sqrt{\cfrac{4}{9}}=s\implies \cfrac{\sqrt{4}}{\sqrt{9}}=s\implies \cfrac{2}{3}=s
3 0
3 years ago
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