A mountaineer climbed 1000 feet at a rate of x feet/hour
1000 = x ( t 1 ) eq1
5000 = X ( t 2) eq2 ( he climbed additional at different rate )
the rate was 10 feet / hour less than twice the first rate
X = 2x - 10 eq3
take eq1 and eq 2
( total time = t 1 + t 2 = T)
T = 1000/x + 5000/X
but X = 2x-10
T = 1000/x + 5000/( 2x -10)
T = 1000/x + 5000/( 2(x-5))
T = 1000/x + 2500 / (x-5)
Answer:
25
Step-by-step explanation:
17 / 0.68 = 25
check your answer?
25 * 0.68 = 17
:)
Answer:
a= -19 :)
Step-by-step explanation:
thats it lol
Answer: x=2
Step-by-step explanation:
