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Oduvanchick [21]
3 years ago
7

A newspaper used a chart resembling the one to the right to illustrate the rising amounts that a video rental company spends to

provide streaming content online. Is this the bar chart of a categorical​ variable, or is it a timeplot that uses bars to show the​ data?

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

This question is incomplete- no bar chart was included.  

The complete question was gotten from google.

A newspaper used a chart resembling the one to the right to illustrate the rising amounts that a video rental company spends to provide streaming content online. Is this the bar chart of a categorical​ variable, or is it a timeplot that uses bars to show the​ data?

Open the attachment below to see the bar chart'

Answer:

A newspaper used a chart resembling the one to the right to illustrate the rising amounts that a video rental company spends to provide streaming content online. Is this the bar chart of a categorical​ variable, or is it a time plot that uses bars to show the​ data? It is a time plot that uses bars to show the data; because it graphs a series of data recorded over time; presenting the values in sequential order.

Step-by-step explanation:

The chart used in the newspaper to illustrate the rising amounts that a video rental company spends to provide streaming content online is a time plot that uses bars to show the data; because it graphs a series of data recorded over time; presenting the values in sequential order.

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Umnica [9.8K]

The value of x is 5

<h3>What are algebraic expressions?</h3>

Algebraic expressions are expressions made up;

  • Factors
  • variables
  • terms
  • constants

They also consist of mathematical operations such as addition, multiplication, division, subtraction, parenthesis, brackets, etc

We have the expression as;

7.5x = 5.5x + 10

collect like terms

7.5x - 5.5x = 10

subtract the like terms

2.0x = 10

Make 'x' the subject

x = 10/2. 0

x = 5

Thus, the value of x is 5

Learn more about algebraic expressions here:

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7 0
2 years ago
WILL GIVE BRAINLIEST IF CORRECT ANSWER!!!
Rom4ik [11]

Answer : 2√3

<u>Given </u><u>:</u><u>-</u>

  • A equilateral triangle with side length 4.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x in the given figure.

As we know that in a equilateral triangle , perpendicular bisector , angle bisector and median coincide with each other .

  • So the perpendicular drawn in the figure will bisect the given side .
  • Therefore the value of each half will be 4/2 = 2 .

Now we may use Pythagoras theorem as ,

→ AB² = BC² + AC²

→ 4² = 2² + x²

→ 16 = 4 + x²

→ x² = 16-4

→ x² = 12

→ x =√12 = √{ 3 * 2²}

→ x = 2√3

<u>Hence </u><u>the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>2</u><u>√</u><u>3</u><u> </u><u>.</u>

I hope this helps.

3 0
2 years ago
Which of the following are adjacent angles?
pickupchik [31]

Answer:

The first option

Step-by-step explanation:

Adjacent angles are just two angles next to each other

3 0
3 years ago
Read 2 more answers
NO =14 and MO =18 determine the length MN
kvasek [131]

Answer:

Step-by-step explanation:

MN=MO+NO

MN=14+18

MN=32

hope i helped.

7 0
3 years ago
(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi
Drupady [299]

Answer:

a. \dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. x(t) = 6\frac{2}{3} \cdot c \cdot t

c. c  = \dfrac{3}{8}  \ g/L

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx =  (5·c - 5·c/3)×dt = 20/3·c = 6\frac{2}{3} \cdot c \cdot dt

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. The amount of salt, x after t minutes is given by the relation

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

dx = 6\frac{2}{3} \cdot c \cdot dt

x(t) = \int\limits \, dx  = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt

x(t) = 6\frac{2}{3} \cdot c \cdot t

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10

6\frac{2}{3} \times c  =\dfrac{25 \ grams }{10}

c  =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} }  = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200}  \ g/L = \dfrac{3}{8}  \ g/L

c  = \dfrac{3}{8}  \ g/L

4 0
3 years ago
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