The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Let the distance from the engineer to the base of the building be x, then
tan 22 = 450/x
x = 450/tan 22 = 1,113.79
Therefore the distance from the engineer to the base of the building to the nearest foot = 1,114 feet
41.4 wph because if you divide 207 by 5 you get 41.4
Answer:
the surface area of the square pyramid is 576.66 cm^2
Step-by-step explanation:
The computation of the surface area of square pyramid is given below:
A = a^2 + 2a × √a^2 ÷ √4 + √h^2
where
a = 12 cm
h = 17 cm
Now put the value of a and h in the above formula
= 12^2 + 2(12) × √12^2 ÷ √4 + √17^2
= 576.66 cm^2
hence, the surface area of the square pyramid is 576.66 cm^2
Answer:
need points sorry 38484343
Step-by-step explanation:
