It allows scientists to visualize the molecule they are working with more vividly.
It also allows them to see the ratio of atoms It contains which further allows
scientist to find the proportions of chemicals to mix together to maximize the
efficiency of a chemical reaction.
Answer:
the final temperature is T=305.63 K
Explanation:
using the Stephan-Boltzmann equation for black bodies
q = σ*(T⁴-T₀⁴)
where
q= heat flux = 155 W/m²+150 W/m² = 255 W/m²
σ= Stephan-Boltzmann constant = 5.67*10⁻⁸ W/m²K⁴
T= absolute temperature
T₀= absolute initial temperature = 255 K
solving for T
q = σ*(T⁴-T₀⁴)
T = (q/σ + T₀⁴)^(1/4)
replacing values
T = (q/σ + T₀⁴)^(1/4) = (255 W/m²/(5.67*10⁻⁸ W/m²K⁴) + (255 K)⁴)^(1/4) = 305.63 K
T=305.63 K
thus the final temperature is T=305.63 K
The question has mentioned three solvents: water, ethanol, and diethyl ether. Water is miscible with ethanol but not diethyl ether. As a result, it would be possible to separate a mixture of water and diethyl ether with a separatory funnel but not a mixture of water and ethanol using such techniques.
Substance X dissolves well in diethyl ether but not in water; substance Y dissolves well in water but not in diethyl ether. As a result, the two components of this mixture would end up in different layers when dissolved in a mixture of water and diethyl ether- which separate into two layers itself. One would expect to find
- a solution mostly of substance X in the diethyl ether layer, and
- a solution mostly of substance Y in the water layer.
Given the fact that diethyl ether has a density less than that of water ( as opposed to ,) it would form the upper layer of its mixture with water. Separate the mixture with a separatory funnel. The question stated that both X and Y are under the solid state while the two solvents are both liquidsm implying that the boiling points of both species are higher than that of their respective solvent. Therefore heat the solutions till all solvent had evaporated to obtain X and Y.
Answer:
44.62 kJ
Explanation:
Firstly, we calculate the energy needed to heat the liquid (ethyl alcohol) by using the formula:
Q = m × c × ∆T
Where;
Q = Amount of heat (J)
m = mass (g)
c = specific heat of ethyl alcohol = 2.138 J/g°C
∆T = change in temperature (°C)
According to the information given in this question;
Q = ?, m = 50.0g, ∆T = (78.4°C - 60°C) = 18.4°C
Therefore, using Q = mc∆T
Q = 50 × 2.138 × 18.4
Q (amount of energy needed to heat ethyl alcohol) = 1966.96 J
Next, we calculate and add the amount of heat needed to vaporize by using the formula;
How many kilojoules of energy are required to heat 50.0 g of ethyl alcohol from 60.0 °C to 78.4 °C and vaporize it? The specific heat of ethyl alcohol is heat of vaporization is 853 J/g.