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ryzh [129]
3 years ago
11

A 13.0 kg iron weightlifting plate has a volume of 1650 cm3 . What is the density of the iron plate in g/cm3?

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
8 0
11.0 kg = (11.0 kg)(1000 g/kg) = 11000 g
(11000 g)/(1400 cm3) = 7.857 g/cm3
Simplified = 7.86 g/cm3
Oksi-84 [34.3K]3 years ago
5 0

Explanation:

It is known that density is the amount of mass divided by volume.

Mathematically,     Density = \frac{mass}{volume}

It is given that mass is 13.0 kg or 13000 g (as 1 kg = 1000 g). And, volume is 1650 cm^{3}.

Therefore, calculate the density as follows.

                    Density = \frac{mass}{volume}

                                 = \frac{13000 g}{1650 cm^{3}}    

                                 = 7.87 g/cm^{3}

Thus, we can conclude that density of the given iron plate is 7.87 g/cm^{3}.

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hichkok12 [17]

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3 0
3 years ago
A solution of 0.2 M Sulfuric acid is titrated with a 0.2 M basic solution. In three to five sentences, explain how you can use t
SCORPION-xisa [38]

If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.

The reaction of sulfuric acid and a basic solution BOH occurs as follows;

H2SO4(aq) + 2BOH(aq) -----> B2SO4(aq) + 2H2O(l)

In the question, we are told that that both the solution of the sulfuric acid and the basic solution are 0.2 M.

The point where all the hydrogen and hydroxide ions have reacted according to the stoichiometry of the reaction. If there is really equimolar amounts of acid and base, the concentration of hydrogen and hydroxide ions will be equal at equivalence point.

Learn more: brainly.com/question/2192784

5 0
3 years ago
Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4
krok68 [10]

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding  

6 0
3 years ago
The vapor pressure of water at 45oC is 71.88 mmHg. What is the vapor pressure of a sugar (C12H22O11) solution made by dissolving
Tju [1.3M]

Answer:

69.79 mmHg is the pressure for the solution

Explanation:

Formula for vapor pressure lowering:

Vapor pressure of pure solvent(P°) - Vapor pressure of solution (P') = P° . Xm

Xm → Molar fraction of solute (moles of solute / Total moles)

Total moles = Moles of solute + Moles of solvent

Let's determine the moles:

50.36 g . 1mol/342 g = 0.147 moles of sugar

88.69 g. 1mol/ 18g = 4.93 moles of water

Total moles = 0.147 + 4.93 = 5.077 moles

Xm = 0.147 / 5.077 = 0.0289

If we replace data given in the formula:

71.88 mHg - P' = 71.88 mmHg . 0.0289 . 0.0289

P' = - (71.88 mmHg . 0.0289 - 71.88 mmHg)

P' = 69.79 mmHg

5 0
2 years ago
What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro
KengaRu [80]

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

3 0
3 years ago
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