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stealth61 [152]
3 years ago
8

15 points -Christina went to a soap box derby race with 12 coins in her pocket that totaled to $1.20 what could those coins be ?

Give 3 different answers plz help ASAP thank you plz give 3 ways I will give brainleiiest
Mathematics
1 answer:
Licemer1 [7]3 years ago
3 0
1. 12 dimes
2. 10 dimes 2 nickles
3. 4 quarters, 3 nickels, 5 Penny's
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PLease send explanation.
Svetach [21]

Answer:

Step-by-step explanation:

XY = 1/2 * QR (According to the midpoint theorem)

=1/2 * 15.6

=15.6/2

=7.8 m

7 0
2 years ago
Read 2 more answers
There are 144 leaves on a tree outside of school. Each week the tree loses 8 leaves. How many leaves will be remaining on the tr
olga_2 [115]

Answer:

96

Step-by-step explanation:

Day 1: 144-8= 136

Day 2: 136-8= 128

Day 3: 128-8= 120

Day 4: 120-8= 112

Day 5: 112-8= 104

Day 6: 104-8=96

4 0
3 years ago
Quadrilateral ABCD is a rectangle. If AG = -7j + 7 and DG = 5j + 43, find BD
Kaylis [27]

<em>BD</em> = 56

Step-by-step explanation:

Step 1: In rectangle, the diagonals are congruent and bisect each other.

So, <em>AC</em> = <em>BD</em>

⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>

⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>

⇒ 2<em>AG</em> = 2<em>GD</em>

⇒<em>AG</em> = <em>GD</em>

⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43

⇒–7<em>j</em> – 5<em>j</em> = 43 – 7

⇒–12<em>j</em> = 36

⇒<em>j</em> = –3

Step 2: <em>BD</em> = 2<em>DG</em>

<em>BD</em> = 2(5<em>j</em> + 43)

     = 2(5 (–3) + 43)

     = 2(–15 + 43)

     = 2 × 28

     = 56

Hence, <em>BD</em> = 56.

4 0
3 years ago
Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9
a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is x^2+4x-21=0. We need to find the solution of this equation.

If the equation is in the form of ax^2+bx+c=0, then its solutions are given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7

So, the solutions of the quadratic equation are 3 and -7.      

6 0
3 years ago
The population of Algebraville is 500,000 and growing at 6.25%. How many people will live in Algebraville in 10 years? 20?
otez555 [7]
This would be exponential growth
A= 500,000(1+.0625)^10
=500,000(1.0625)^10
=500,000* <span>1.83353577126
the population after 10 years= </span><span>916,767
A=500,000(1+.0625)^20
=500,000(1.0625)^20
=500,000* 3.36185342451
the population after 20 years would be= </span><span>1,680,926</span>
8 0
3 years ago
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