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n200080 [17]
3 years ago
8

Please help me ]ppppppppppppppp​

Mathematics
1 answer:
sergey [27]3 years ago
3 0

Answer:

the answer would be -16j2k or the last choice.

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I need help with this math problem
den301095 [7]

Answer:

1). \frac{2}{x^{2}-x-12 }=\frac{2}{(x+3)(x-4)}

2). \frac{1}{x^{2}-16 }=\frac{1}{(x-4)(x+4)}

Step-by-step explanation:

In this question we have to write the fractions in the factored form.

Rational expressions are \frac{2}{x^{2}-x-12 } and \frac{1}{x^{2}-16 }.

1). \frac{2}{x^{2}-x-12 }

Factored form of the denominator (x² - x - 12) = x² - 4x + 3x - 12

                                                                           = x(x - 4) + 3(x - 4)

                                                                           = (x + 3)(x - 4)

Therefore. \frac{2}{x^{2}-x-12 }=\frac{2}{(x+3)(x-4)}

2). \frac{1}{x^{2}-16 }

Factored form of the denominator (x² - 16) = (x - 4)(x + 4)

[Since (a²- b²) = (a - b)(a + b)]

Therefore, \frac{1}{x^{2}-16 }=\frac{1}{(x-4)(x+4)}

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Step-by-step explanation:

ln(2a^3 /b^4)

We know that ln(x/y) = ln (x) - ln y

ln(2a^3 ) - ln (b^4)

We know that ln (xy) = ln x + ln y

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We know that ln(x^y) = y ln (x)

ln(2) + 3ln(a) - 4ln (b)

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Step-by-step explanation:

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Step-by-step explanation:

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