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3 years ago

If 20 tickets cost $27, what is the unit rate of tickets?

Mathematics

2 answers:

3241004551 [841]3 years ago

4 0

If 20 tickets cost $27, the unit price would be $0.74.

katen-ka-za [31]3 years ago

3 0

The answer would be 0.740 as a repeating decimal. Think about it logically, you cannot have anything that is less than a cent. You can say that a ticket is 74 cents each. ( I could be wrong)

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A data value is considered _______ if its z-score is less than minus2 or greater than 2.

elena-14-01-66 [18.8K]

Answer:

Unusual

Step-by-step explanation:

we know that

The z-score is a measure of how close the given data point is to the mean of the values given with the standard deviation

if its z-score is greater than or equal to -2, or less than or equal to 2., then the data value is considered ordinary

if its z-score is less than -2 or greater than 2, then the data value is considered unusual

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3 years ago

Find the value of two numbers is their sum is 12 and there difference is 4

weqwewe [10]

8 and 4
8+4=12
8-4=4
hope this helps

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3 years ago

Ahat contains pieces of paper marked with the numbers 1 through 16. Is the

Anika [276]

Answer:as likely as not

Step-by-step explanation:

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3 years ago

Read 2 more answers

g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o

natali 33 [55]

Answer:

The tangent line to the given curve at the given point is $y=9x-26$ .

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of $y=2x^2-7x+6$ and then evaluate it for $x=4$ .

$(y=2x^2-7x+6)'$ Differentiate the equation.

$(y)'=(2x^2-7x+6)'$ Differentiate both sides.

$y'=(2x^2)'-(7x)'+(6)'$ Sum/Difference rule applied: $(f(x)\pmg(x))'=f'(x)\pm g'(x)$

$y'=2(x^2)'-7(x)'+(6)'$ Constant multiple rule applied: $(cf)'=c(f)'$

$y'2(2x)-7(1)+(6)'$ Applied power rule: $(x^n)'=nx^{n-1}$

$y'=4x-7+0$ Simplifying and apply constant rule: $(c)'=0$

$y'=4x-7$ Simplify.

Evaluate y' for x=4:

$y'=4(4)-7$

$y'=16-7$

$y'=9$ is the slope of the tangent line.

Point slope form of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Insert 9 for $m$ and (4,10) for $(x_1,y_1)$ :

$y-10=9(x-4)$

The intended form is $y=mx+b$ which means we are going need to distribute and solve for $y$ .

Distribute:

$y-10=9x-36$

Add 10 on both sides:

$y=9x-26$

The tangent line to the given curve at the given point is $y=9x-26$ .

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function $f(x)=2x^2-7x+6$ at $x=4$ (the slope of the tangent line at $x=4$ ):

$\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}$

$\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}$ We are given f(4)=10.

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

$2x^2-7x-4=(x-4)(2x+1)$

Let's check this with FOIL:

First: $x(2x)=2x^2$

Outer: $x(1)=x$

Inner: $(-4)(2x)=-8x$

Last: $-4(1)=-4$

---------------------------------Add!

$2x^2-7x-4$

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

$\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}$

$\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}$

$\lim_{x \rightarrow 4}(2x+1)$

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0

3 years ago

The entire pink figure has been transformed to create the new blue image. Describe the transformation that has taken place.

Leno4ka [110]

Answer:

D. (bottom right)

Step-by-step explanation:

If there is a line where y = x, that means that y and x can both equal 1, 2, 3, -1, -2, -3, etc. They are just always the same. This line, then, would pass through (just for example) (-4, -4) and (4, 4). If you reflect the pink figure across that line, you will get the blue figure. Hope this helps!

6 0

3 years ago