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4 years ago

The letters a,b and c, represent nonzero constants. Solve ax+b=c for x

Mathematics

1 answer:

insens350 [35]4 years ago

4 0

Answer:

$x = \frac{c-b}{a}$

Step-by-step explanation:

To solve for x, x needs to be on one side while all the other variables are on the other

To do this first subtract b from each side making the equation,

ax = c - b

Now divide by a on both sides. This means that to solve for x the equation must be ...

$x = \frac{c-b}{a}$

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3 years ago

Find the area and perimeter of an isosceles trapezoid with legs 25cm and bases 16cm and 30cm

Varvara68 [4.7K]

A=1/2h(b1+b2)
= 1/2(h)(30+16)
>how to find h<
>30-16= 14/2 = 7<
>25²-7² = 625-49 = 576<
>√576 = 24 .. h=24<
= 1/2(24)(30+16)
= 12(46)
A = 552 cm²
P= b+b+l+l
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3 years ago

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(40 pts)can you factor the difference of square?perfect square trinomials?

stira [4]

Answer:

Step-by-step explanation:

The difference of two squares may be represented by the formula: a^2-b^2,

which can be factored as (a+b)(a-b)

A perfect square trinomial may be represented by the formula: a^(2)-2ab+b^2 or a^(2)+2ab+b^2, depending on the sign of b

if b is negative: use the formula a^(2)-2ab+b^2, which can be factored as (a-b)*(a-b) or (a-b)^(2)

if b is positive: use the formula a^(2)+2ab+b^2, which can be factored as (a+b)*(a+b) or (a+b)^(2)

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3 years ago

If your annual salary is $64,710, what is your semimonthly salary?

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3 years ago

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Identify each x-value at which the slope of the tangent line to the function f(x) = 0.2x2 + 5x − 12 belongs to the interval (-1,

Misha Larkins [42]

Answer:

slope of the tangent

$\frac{d y}{d x} = 0.2(2 x) + 5 (1)$

The slope of the tangent to the interval (-1 ,1)

m = 4.6 ,5, 5.4

Step-by-step explanation:

Step(i):-

Given function is f(x) = 0.2 x² + 5 x − 12

Slope of the tangent formula

$m = \frac{d y}{d x}$

Let y = f(x) = 0.2 x² + 5 x − 12 ...(i)

Differentiating equation(i) with respective to 'x' , we get

$\frac{d y}{d x} = 0.2(2 x) + 5 (1) -0$

let x=-1

$m = \frac{dy}{dx} = 0.2 (2 X -1) +5 = 4.6$

let x=0

m = 5

let x=1

$m = \frac{dy}{dx} = 0.2 (2 X 1) +5 = 5.4$

conclusion:-

slope of the tangent

$\frac{d y}{d x} = 0.2(2 x) + 5 (1)$

The slope of the tangent to the interval (-1 ,1)

m = 4.6 , 5, 5.4

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3 years ago

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