here we have to find the quotient of '(16t^2-4)/(8t+4)'
now we can write 16t^2 - 4 as (4t)^2 - (2)^2
the above expression is equal to (4t + 2)(4t - 2)
there is another expression (8t + 4)
the expression can also be written as 2(4t + 2)
now we have to divide both the expressions
by dividing both the expressions we would get (4t + 2)(4t - 2)/2(4t + 2)
therefore the quotient is (4t - 2)/2
the expression comes out to be (2t - 1)
Answer:
Part a) The ratio of the perimeters is 
Part b) The ratio of the areas is 
Step-by-step explanation:
Part A) What is the value of the ratio (new to original) of the perimeters?
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
Let
z-----> the scale factor
x-----> the perimeter of the new triangle
y-----> the perimeter of the original triangle

we have

substitute

Part B) What is the value of the ratio (new to original) of the areas?
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> the area of the new triangle
y-----> the area of the original triangle

we have

substitute


You could add the whole number parts first then add the fractions. Finally add the 2 results.
Answer:
x = 5
Step-by-step explanation:
To find the value of x make sure to get it on one side
First subtract 3x from each side. This makes the equation now
3x + 2 = -8 + 25
Now see what 25 subtract by 8 is (17)
3x + 2 = 17
Next subtract 2 from both sides
3x = 15
Lastly, divide 15 by 3, making x equal 5
x = 5