Answer:
let the numbers be x and y then by given conditions:
x + y = 10 ….. eq 1
and
xy = 9….. eq 2
from eq 2. y = 9/x
put this in eq. 1
x + 9/x = 10
x + 9= 10x
x = 1
now,
xy = 9put value of x
y = 9
Step-by-step explanation:
Hope it is helpful....
Answer:
36
Step-by-step explanation:
A square has equal sides.
Area= lenth * width
6*6=36
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
Answer: Half of a apple pie
Step-by-step explanation:
1/2 is half
Step-by-step explanation:
