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4 years ago

The function of the ___________________ system is to keep the human species on this planet.

1 answer:

4 0

The function of the "Reproductive" <span>system is to keep the human species on this planet.

Hope this helps!</span>

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A Scooter with a mass of 50 kilograms travels with a speed of 10 meters per second. A 2 Nt force bring it to a halt. How long ti

Serga [27]

Answer:

250s

Explanation:

Given parameters:

Mass = 50kg

Speed = 10m/s

Force = 2N

Unknown:

Time the force was acting = ?

Solution:

To solve this problem, we use the equation of motion from the second law of Newton:

Ft = mV

F is the force

t is the time taken

m is the mass

V is the velocity

2 x t = 50 x 10

t = 250s

3 0

3 years ago

A 2000 Hz siren and a civil defense official are both at rest with respect to the ground. What frequency does the official hear

astra-53 [7]

Answer:

a) $f_1 = 2070.6 Hz$

b) $f_2 = 1929.4 Hz$

Explanation:

Apparent frequency of the siren is given as

$f = \frac{v_{rel}}{\lambda}$

as we know that the wavelength will remain the same as it is having originally

sowe know

$\lambda = \frac{340}{2000}$

$\lambda = 0.17 m$

a) Now when wind is blowing from source to official

so we have

$v_{rel} = 340 + 12 = 352 m/s$

so we have

$f_1 = \frac{352}{0.17}$

$f_1 = 2070.6 Hz$

b) Now when wind is from official to source

so we have

$v_{rel} = 340 - 12 = 328 m/s$

so we have

$f_2 = \frac{328}{0.17}$

$f_2 = 1929.4 Hz$

4 0

4 years ago

Which factor should change when comparing the boiling times of the liquids?

Andru [333]

Answer: B

Explanation:

7 0

3 years ago

Read 2 more answers

The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample

Bezzdna [24]

Answer:

4589.05 year

Explanation:

The relation of activity is given by $A=A_0e^{\lambda t}$ we have given $\frac{A}{A_0}=0.574$

Half life $T=5730\ years$

We know that half life $T=\frac{0.693}{\lambda }$

$\lambda =\frac{0.693}{5730}=1.2094\times 10^{-4}\ per\ year$

So $0.574=e^{-1.2094\times 10^{-4}t}$

$e^{1.2094\times 10^{-4}t}=\frac{1}{0.574}=1.742$

${1.2094\times 10^{-4}t}=ln1.742=0.555$

$t=\frac{0.555}{1.2094\times 10_{-4}}=4589.05\ year$

7 0

3 years ago

The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g o

satela [25.4K]

Answer:

Q = 50.25 [J]

Explanation:

To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.

Q = m*Cp*(DT)

where:

Q = energy in form of heat [J]

m = mass = 5 [g] = 0.005 [kg]

Cp = specific heat = 1005 [J/kg*°C]

DT = temperature change = 10 [°C]

Now replacing:

Q = 0.005*1005*10

Q = 50.25 [J]

4 0

3 years ago